Quadratic Equation
BasicSolve quadratic equations, use factorisation method and formula method.
After this lesson, you can:
- Quadratic equation highest degree 2
- First rearrange to ax² + bx + c = 0
- If can factorise use factorisation method
Before this lesson you should know: Factorisation
1Summary 重點摘要
Solve quadratic equations, use factorisation method and formula method.
2Vocabulary cards Vocabulary
Q
Quadratic equation一元二次方程
Equation highest degree 2, e.g. x² + 5x + 6 = 0.
R
Root根
Answer of equation, x value that makes equation equal 0.
S
Solve解方程
Find all roots of equation.
F
Factorisation method因式分解法
Factorise left side, then each factor equals 0 to solve.
Q
Quadratic formula二次方程公式
x = (-b ± √(b² - 4ac)) / 2a, general method.
D
Discriminant判別式
b² - 4ac, used to judge how many real roots.
T
Two roots兩個根
Quadratic equation usually has two answers.
Z
Zero product零乘積性質
If A × B = 0, then A = 0 or B = 0.
3Step by step Steps
- Step 1: Write in standard formThe first step in solving a quadratic equation is to rearrange it into the standard form ax² + bx + c = 0, where a is not zero. Move every term to the left side so the right side becomes 0, then arrange the terms in descending powers of x and collect like terms. This matters because only after identifying the coefficients a, b and c can we factorise correctly or substitute into the formula. A common mistake is forgetting to flip the sign when moving a term across the equals sign.
- Step 2: Try factorisationNext, try to factorise the left side into a product of two linear factors. A common technique is the cross-method: when a = 1, look for two numbers whose product is c and whose sum is b. Factorisation is preferred whenever possible because it is faster than the formula and less prone to arithmetic errors. A common mistake is skipping the check: expand the factors once to confirm the middle term matches the original expression.
- Step 3: Zero product propertyApply the zero product property: if the product of two expressions equals 0, then at least one of them must be 0. That is, when A × B = 0, we must have A = 0 or B = 0. This property is the key that turns a product form into two linear equations. It only works when the right side is already 0. A common mistake is taking square roots of both sides or cancelling a factor, which loses a root.
- Step 4: Solve each linear equationSet each factor equal to 0 and solve the two linear equations separately to obtain two roots. For example, from (x + 2)(x + 3) = 0 we solve x + 2 = 0 and x + 3 = 0, giving x = -2 or x = -3. A quadratic equation generally has two real roots, so both equations must be solved. A common mistake is forgetting to flip the sign when moving a constant to the other side.
- Step 5: Use the formula when factorisation failsIf factorisation does not work, for example when the coefficients are large or the roots are irrational, use the quadratic formula x = (-b ± √(b² - 4ac)) / 2a, which applies to every quadratic equation. Before substituting, confirm the equation is in standard form and read the signs of a, b and c carefully. The nature of the roots is decided by the discriminant b² - 4ac. A common mistake is forgetting brackets around negative values of b or c.
- Step 6: Check the answersFinally substitute both roots into the original equation to confirm the left side really equals 0. Checking reveals factorisation errors or sign slips immediately and costs very little time in an exam. Substitute into the original equation rather than a factorised intermediate form, otherwise the earliest mistake stays hidden. If a root does not give 0, recheck step by step from the standard form.
4Diagrams Diagrams
5Worked example Example
Example: Solve the quadratic equation x² + 5x + 6 = 0.
- Step 1: The equation is already in standard form, so read off a = 1, b = 5 and c = 6, because the signs of the coefficients must be clear before using any method.
- Step 2: Factorise the left side by the cross-method, finding two numbers with product 6 and sum 5, giving x² + 5x + 6 = (x + 2)(x + 3).
- Step 3: Apply the zero product property: (x + 2)(x + 3) = 0 gives x + 2 = 0 or x + 3 = 0, because a product of 0 forces at least one factor to be 0.
- Step 4: Solve the two linear equations separately by moving the constants across, giving x = -2 and x = -3, because subtracting equal amounts from both sides keeps equality.
- Step 5: Check by substituting x = -2 into the left side: (-2)² + 5(-2) + 6 = 4 - 10 + 6 = 0, because a solution must satisfy the original equation.
- Answer: x = -2 or x = -3. Substituting either value into the original equation makes the left side equal 0, so the check passes; since the discriminant is positive, the equation has two distinct real roots, and both answers must be written down.
6Common mistakes Mistakes
✗ ✗ Forget negative sign: (x+2)(x+3) = 0 → x = 2, x = 3
✓ ✓ x+2 = 0 → x = -2! Must move term change sign!
✗ ✗ Miss one root
✓ ✓ Quadratic equation usually has two roots, don't miss!
✗ ✗ Not rearrange to = 0 then solve
✓ ✓ Must rearrange equation to = 0 first then solve!
7Quick check Quick check
Q1Roots of (x-1)(x-3) = 0?
Answer: x = 1 or x = 3
Did you get it right?
Q2Quadratic equation standard form?
Answer: ax² + bx + c = 0
Did you get it right?
Q3Zero product property?
Answer: A × B = 0 → A=0 or B=0
Did you get it right?
Q4Roots of x² - 4 = 0?
Answer: x = 2 or x = -2
Did you get it right?
Q5Discriminant is?
Answer: b² - 4ac
Did you get it right?
8Recap Recap
- Quadratic equation highest degree 2
- First rearrange to ax² + bx + c = 0
- If can factorise use factorisation method
- Zero product: A × B = 0 → A=0 or B=0
- Can't factorise then use quadratic formula