Quadratic Inequality
BasicSolve quadratic inequalities, use opening up/down method.
After this lesson, you can:
- Solve inequality first solve equation find roots
- See quadratic term positive/negative judge opening
- Opens up: > 0 two sides, < 0 middle
Before this lesson you should know: Quadratic Equation
1Summary 重點摘要
Solve quadratic inequalities, use opening up/down method.
2Vocabulary cards Vocabulary
I
Inequality不等式
Expression with > < ≤ ≥, e.g. x + 2 > 5.
S
Solution解集
All x values that satisfy inequality.
G
Greater than大於
More than, symbol >.
L
Less than小於
Less than, symbol <.
R
Roots根
Points where equals 0, split number line into three parts.
O
Opening up開口向上
Quadratic term positive, parabola opens up.
I
Interval區間
Range between two numbers.
N
Number line數線
Line with scales, used to show range.
3Step by step Steps
- Step 1: Solve the related equationTo solve a quadratic inequality, first pretend the inequality sign is an equals sign and solve the related quadratic equation to find its two roots. These roots are the critical values on the number line, because the sign of a quadratic expression can only change where it passes through a root. Factorisation or the quadratic formula both work, exactly as in solving an equation. A common mistake is finding roots before converting to standard form, which leads to wrong coefficients.
- Step 2: Decide the direction of openingNext look at the sign of the quadratic coefficient a to decide how the parabola opens: when a is positive it opens upward like a bowl, and when a is negative it opens downward, the other way up. The direction decides which regions give values above 0 and which give values below 0, so it must be settled first. In standard form, a is simply the coefficient of the x² term. A common mistake is misreading the sign, for example treating -x² as x².
- Step 3: Mark the roots on a number lineMark the two roots on a number line, which is now split into three regions: left of both roots, between them, and right of both. Since the sign of a quadratic only changes at a root, the sign is constant within each region, so testing one point per region is enough. When drawing endpoints, watch the strictness of the inequality: use open circles for > or <, and solid dots for ≥ or ≤. A common mistake is swapping the positions of the two roots.
- Step 4: Judge when the curve opens upwardWhen the parabola opens upward, its two ends rise without bound while the middle dips below the x-axis. Hence the solution of the quadratic being greater than 0 lies in the two outer regions, and the solution of it being less than 0 lies between the roots. For example, x² + 5x + 6 > 0 gives x smaller than the smaller root or larger than the larger root. Test points such as 0 are quickest. A common mistake is mixing up the outer and middle regions, which inverts the answer.
- Step 5: Judge when the curve opens downwardWhen the parabola opens downward the situation reverses: the middle rises above the x-axis while the two ends fall away. Hence the expression is greater than 0 between the roots and less than 0 outside them. Do not memorise blindly; sketch a quick curve and read the answer from where the graph sits relative to the x-axis, so both cases stay clear. A common mistake is copying the upward-opening conclusion without adjusting for the direction.
- Step 6: Write the solution setFinally write the answer as intervals and decide whether endpoints are included: for strict > or < the endpoints are excluded, written as x < a or x > b; for ≥ or ≤ the endpoints are included and the symbols must show it. A two-sided answer needs the word or to join the parts, while a middle region is written as one interval. A common mistake is dropping endpoints in an inclusive problem, or writing two outer regions as a single interval.
4Diagrams Diagrams
5Worked example Example
Example: Solve the quadratic inequality x² + 5x + 6 > 0.
- Step 1: Solve the related equation x² + 5x + 6 = 0 by the cross-method, giving (x + 2)(x + 3) = 0, so the roots are x = -2 and x = -3, because 6 splits into 2 and 3 whose sum is 5.
- Step 2: Look at the quadratic coefficient: the coefficient of x² is +1, which is positive, so the parabola opens upward, because the sign of that coefficient decides the direction of opening.
- Step 3: Mark -3 and -2 on a number line, splitting it into three regions, and choose one test point in each, for example -4, -2.5 and 0, because the sign is constant within each region.
- Step 4: Substitute the test points: at x = -4 the left side is 16 - 20 + 6 = 2, positive; at x = -2.5 it is 6.25 - 12.5 + 6 = -0.25, negative, so the middle region is negative and the two outer regions are positive.
- Step 5: Since the curve opens upward and we need values above 0, the solution is the two outer regions, written as x < -3 or x > -2; because the inequality is strict, the endpoints -3 and -2 are excluded.
- Answer: x < -3 or x > -2. The test points show that the outer regions give positive values while the middle region gives a negative value, and since the parabola opens upward, the part above 0 is exactly the two outer regions; because the inequality is strict, the endpoints are excluded and the two intervals must be joined by the word or.
6Common mistakes Mistakes
✗ ✗ Forget opening direction, always middle
✓ ✓ Opens up and down are opposite!
✗ ✗ > and < mixed up
✓ ✓ Opens up: > 0 is two sides, < 0 is middle!
✗ ✗ Divide negative not change sign
✓ ✓ Multiply/divide inequality by negative, sign must flip!
7Quick check Quick check
Q1Solution of x² + 5x + 6 < 0?
Answer: -3 < x < -2
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Q2Quadratic term positive, opens?
Answer: Up
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Q3Opens up, > 0 is?
Answer: Two sides
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Q4Multiply inequality by negative must?
Answer: Flip sign
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Q5Solution written in?
Answer: Interval
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8Recap Recap
- Solve inequality first solve equation find roots
- See quadratic term positive/negative judge opening
- Opens up: > 0 two sides, < 0 middle
- Opens down: > 0 middle, < 0 two sides
- Multiply/divide negative must flip sign