Arithmetic and Geometric Sequences
IntermediateLearn arithmetic and geometric sequences, find nth term and sum.
After this lesson, you can:
- Arithmetic: each term add fixed d
- Geometric: each term multiply fixed r
- Arithmetic nth term: a + (n-1)d
Before this lesson you should know: Indices and Logarithms
1Summary 重點摘要
Learn arithmetic and geometric sequences, find nth term and sum.
2Vocabulary cards Vocabulary
S
Sequence數列
Ordered list of numbers, e.g. 1, 3, 5, 7, ...
A
Arithmetic等差
Difference between each term fixed, e.g. 1, 3, 5, 7 difference 2.
G
Geometric等比
Ratio between each term fixed, e.g. 1, 2, 4, 8 ratio 2.
C
Common difference公差
Arithmetic sequence adjacent difference, d.
C
Common ratio公比
Geometric sequence adjacent ratio, r.
n
nth term第 n 項
nth number in sequence.
S
Sum總和
Add first n terms together.
F
First term首項
First number, a.
3Step by step Steps
- Step 1: Recognising arithmetic sequencesAn arithmetic sequence is one in which every term after the first differs from the previous term by the same fixed number d, called the common difference. For example, 1, 3, 5, 7, 9 has common difference 2. To test a sequence, subtract consecutive pairs of terms and confirm the differences are all equal. The common difference may be negative: 10, 7, 4, 1 has d = -3 and decreases; when d = 0 every term is the same, and such a sequence is still arithmetic.
- Step 2: The nth term of an arithmetic sequenceThe nth term of an arithmetic sequence is Tn = a + (n - 1)d, where a is the first term and d the common difference. The formula adds (n - 1) copies of d because moving from the first term to the nth takes n - 1 steps. For a first term of 2 and a common difference of 3, the 10th term is 2 + 9 × 3 = 29. The most common error is writing n instead of (n - 1); before substituting, confirm which term is required and list a and d clearly.
- Step 3: The sum of an arithmetic sequenceThe sum of the first n terms of an arithmetic sequence is Sn = n2 × [2a + (n - 1)d]; when the first and last terms are known, the alternative form Sn = n2 × (first term + last term) may be used. The two formulas are equivalent, and the choice depends on the data given: use the first when a and d are known, the second when both end terms are known. The formula comes from pairing terms at the two ends, where each pair has the same sum and there are n2 pairs; understanding this origin makes the formula easy to remember and use.
- Step 4: Recognising geometric sequencesA geometric sequence is one in which every term after the first is obtained by multiplying the previous term by the same fixed number r, called the common ratio. For example, 1, 2, 4, 8, 16 has common ratio 2. Test by dividing each term by the one before it. When all terms share the same sign, r is positive; a negative r makes the signs alternate, as in 1, -2, 4, -8. The common ratio cannot be 0, otherwise every term from the second onwards becomes 0 and the idea of a ratio collapses.
- Step 5: The nth term of a geometric sequenceThe nth term of a geometric sequence is Tn = a × r^(n-1), where a is the first term and r the common ratio. As with the arithmetic formula, the exponent is n - 1 rather than n, because the first term has not yet been multiplied by any ratio. For a first term of 3 and a ratio of 2, the 5th term is 3 × 2^4 = 48. Watch the order of operations: evaluate r^(n-1) first and then multiply by a, and for large exponents write the steps separately to avoid errors.
- Step 6: The sum of a geometric sequenceThe sum of the first n terms of a geometric sequence is Sn = a × (r^n - 1) / (r - 1), valid when r is not 1; when r = 1 every term equals a and the sum is simply Sn = na. Substitute r and n carefully, and always bracket fractional or negative values of r. The formula arises from the shift-and-subtract trick: subtracting r·Sn from Sn cancels most middle terms, and simplifying what remains produces the formula; knowing this origin helps you apply it correctly.
4Diagrams Diagrams
5Worked example Example
Example: for the arithmetic sequence 2, 5, 8, 11, ..., find the 10th term and the sum of the first 10 terms.
- Step 1: Identify the type: subtracting consecutive terms gives 5 - 2 = 3, 8 - 5 = 3 and 11 - 8 = 3, all equal, so the sequence is arithmetic with common difference 3.
- Step 2: List the data: first term a = 2, common difference d = 5 - 2 = 3, and the required term n = 10; writing the three values down clearly prevents substitution slips.
- Step 3: Substitute into Tn = a + (n - 1)d: T10 = 2 + (10 - 1) × 3 = 2 + 27 = 29, taking care that the factor is (n - 1) and not n, the most common slip.
- Step 4: Find the sum: Sn = n2 × [2a + (n - 1)d] gives S10 = 5 × [4 + 27] = 5 × 31 = 155; checking with the last term, S10 = 102 × (2 + 29) = 155, and the two formulas agree.
- Step 5: Verify by listing: the terms run 2, 5, 8, 11, 14, 17, 20, 23, 26, 29, so the 10th term is indeed 29 and the terms add to 155, confirming both answers.
- Answer: The 10th term is 29 and the sum of the first 10 terms is 155. In the formula Tn = a + (n - 1)d, the factor (n - 1) is the position most often written wrongly, because the first and nth terms are only n - 1 steps apart. The sum formula has two forms: Sn = n2 × [2a + (n - 1)d] when a and d are known, and Sn = n2 × (first term + last term) when the two end terms are known; using both gives a double check. Listing all the terms is the final safeguard and, when time allows, it verifies the term and the total at the same time.
6Common mistakes Mistakes
✗ ✗ Arithmetic multiply: Tn = a + nd
✓ ✓ Tn = a + (n-1)d, not nd!
✗ ✗ Arithmetic sum forget multiply n2
✓ ✓ Sn = n2 × (first + last), don't miss n2!
✗ ✗ Arithmetic difference and geometric ratio mixed up
✓ ✓ Arithmetic add, geometric multiply!
7Quick check Quick check
Q1Arithmetic 1, 3, 5, 7, ... d = ?
Answer: 2
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Q2Geometric 1, 2, 4, 8, ... r = ?
Answer: 2
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Q3Arithmetic nth term formula?
Answer: Tn = a + (n-1)d
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Q4Arithmetic sum = ?
Answer: n2 × (first + last)
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Q5Geometric nth term formula?
Answer: Tn = a × r^(n-1)
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8Recap Recap
- Arithmetic: each term add fixed d
- Geometric: each term multiply fixed r
- Arithmetic nth term: a + (n-1)d
- Arithmetic sum: n2 × (first + last)
- Geometric nth term: a × r^(n-1)