Indices and Logarithms

Intermediate

Learn index laws and basic logarithm operations, know conversion.

For:S4 Mathematics · Unit:Number & algebra · Lesson 6 of 10 in the learning path

After this lesson, you can:
  • Index laws: same base multiply add, divide subtract, power multiply
  • Logarithm is opposite of index
  • a^x = y ↔ log_a y = x
數學Mathematics
Before this lesson you should know: Quadratic Inequality

1Summary 重點摘要

Learn index laws and basic logarithm operations, know conversion.

2Vocabulary cards Vocabulary

I
Index指數

Small number on top right, e.g. 3 in 2³ is index.

B
Base底數

Big number, e.g. 2 in 2³ is base.

L
Logarithm對數

Opposite of index, e.g. log₂8 = 3, because 2³ = 8.

L
Law 1指數定律 1

a^m × a^n = a^(m+n), same base multiply, index add.

L
Law 2指數定律 2

a^m ÷ a^n = a^(m-n), same base divide, index subtract.

L
Law 3指數定律 3

(a^m)^n = a^(mn), power of power, index multiply.

C
Convert互換

a^x = y and log_a y = x are same thing.

C
Common log常用對數

Base 10, e.g. log 100 = 2.

3Step by step Steps

  1. Step 1: Know the index lawsIndex work rests on a few basic laws: multiplying powers with the same base adds the indices, a^m × a^n = a^(m+n); dividing powers with the same base subtracts the indices, a^m ÷ a^n = a^(m-n); and raising a power to a power multiplies the indices, (a^m)^n = a^(mn). Every law requires the bases to be identical before combining. A common mistake is multiplying the indices when multiplying powers: a² × a³ should be a⁵, not a⁶.
  2. Step 2: Simplify index expressionsTo simplify an index expression, first write every part with the same base, then apply the laws in order to combine products and quotients into a single power. A negative index is handled by a^(-n) = 1/(a^n), and a zero index by a⁰ = 1. Apply one law at a time and state the reason, which reduces slips. A common mistake is confusing coefficients with indices: in 2a² × 3a³ the coefficients give 6 and the indices give a⁵.
  3. Step 3: Understand what a logarithm meansA logarithm is the inverse of an index: if a^x = y, where a > 0 and a is not 1, then log_a y = x, read as the logarithm of y to base a. In other words, the logarithm answers the question of how many times the base must multiply itself to reach y. Once the definition is clear, every log calculation can be turned back into an index problem. A common mistake is treating log_a as a coefficient, for example writing log_a y as y ÷ a, which is wrong.
  4. Step 4: Practise converting between formsIndex form and log form convert into each other: 2³ = 8 is equivalent to log₂8 = 3, and 10² = 100 is equivalent to log₁₀100 = 2. Hold on to the definition when practising: the logarithm is simply the index x itself. This conversion is the basic technique for solving log equations, translating any log form into index form before solving. A common mistake is swapping the base and the index, for example writing log₂8 = 3 as 3² = 8.
  5. Step 5: Know the logarithm lawsLogarithms have their own laws: log_a (MN) = log_a M + log_a N, so a product splits into a sum of logs; log_a (M/N) = log_a M - log_a N, so a quotient splits into a difference; and log_a (M^n) = n log_a M, which brings the power out front. The laws need the same base and a positive number inside the log. A common mistake is assuming log(M + N) equals log M + log N; a sum cannot be split this way.
  6. Step 6: Evaluate a logarithmTo evaluate a logarithm reliably, convert it back to index form: let log_a y = x, rewrite as a^x = y, then express y as a power of the base a, and that index is the answer. For example, to find log₃81, since 81 = 3⁴, the answer is 4. If the number inside the log is not an easy power of the base, simplify with the log laws first. A common mistake is ignoring that the log argument must be positive: log₂0 and log₂(-4) are meaningless.

4Diagrams Diagrams

對數:指數嘅逆運算 Logarithms指數形式:2³ = 82 係底 · 3 係指數 · 8 係結果互為逆運算對數形式:log₂8 = 3讀法:「以 2 為底 8 嘅對數係 3」一句理解:log 問嘅係「幾多個底相乘先得到呢個數?」log₁₀1000 = 3(10×10×10) log₂16 = 4 log₅25 = 2常用:log(底 10)· ln(底 e ≈ 2.718)——計數機有專鍵為何要學:地震黎克特制·酸鹼 pH·聲音分貝——全部用對數刻度
Fig. 1: Logarithms

5Worked example Example

Example: Evaluate log₂16.

  1. Step 1: Let log₂16 = x and rewrite it in index form as 2^x = 16, because logarithms and indices are inverse operations.
  2. Step 2: List the powers of 2: 2¹ = 2, 2² = 4, 2³ = 8, 2⁴ = 16, checking one by one to find the index that gives 16.
  3. Step 3: Compare 2⁴ = 16 with 2^x = 16; the two bases are the same, so the indices must be equal, giving x = 4.
  4. Step 4: Check by putting x = 4 back into 2^x: 2⁴ = 16 matches the question, because the index found must make the equation true, confirming log₂16 = 4.
  5. Answer: log₂16 = 4. The key idea is to introduce x and translate the logarithm problem into the index problem 2^x = 16, then read off the answer because 16 is exactly the fourth power of 2; the check 2⁴ = 16 confirms that the logarithm of 16 to base 2 is indeed 4.

6Common mistakes Mistakes

✗ ✗ Different bases add index: 2³ × 3² = 6⁵
✓ ✓ Must same base first can add index!
✗ ✗ log(a+b) = log a + log b
✓ ✓ log a + log b = log(ab), not log(a+b)!
✗ ✗ log₂8 = 8²
✓ ✓ log₂8 = 3, because 2³ = 8!

7Quick check Quick check

Q12³ × 2⁴ = ?

Q2log₃9 = ?

Q3log a + log b = ?

Q4(2³)² = ?

Q5log_a y = x equals?

8Recap Recap

  • Index laws: same base multiply add, divide subtract, power multiply
  • Logarithm is opposite of index
  • a^x = y ↔ log_a y = x
  • log a + log b = log(ab)
  • log a - log b = log(a/b)

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