函數與圖像:二次函數的模樣
IntermediateFunction notation, parabola features and discriminants: the three codes of quadratic graphs.
- f(x) is substitution: bracket negatives.
- Opening follows a: positive up, negative down.
- Vertex (-b2a, f(-b2a)) answers all max-min questions.
文體小知識:函數與圖像——對應 DSE 核心單元「函數及圖像」:由代入求值到二次函數圖像,是 DSE 卷二高頻考點。
1Summary 重點摘要
Function notation, parabola features and discriminants: the three codes of quadratic graphs.
2Vocabulary cards Vocabulary
A rule mapping each x to one output f(x).
The U-shaped graph of a quadratic.
The maximum or minimum point.
Δ=b²-4ac: predicts x-intercepts.
The vertical line through the vertex.
Where the graph crosses the x-axis.
Shifting or flipping a graph.
The y-value at the vertex when a<0.
3Step by step Steps
- Step 1: The notation f(x) is substitutionThe notation f(x) means: take the value inside the brackets and put it in place of x on the right-hand side. For f(x) = 2x - 3, we get f(4) = 2 × 4 - 3 = 5 and f(-1) = 2 × (-1) - 3 = -5. For f(x) = x² + 1, finding f(-2) requires writing (-2)² + 1 = 5 with brackets around the negative number, otherwise it is easily miscalculated as -4. Substitution underpins everything about functions; every point (c, f(c)) on the graph comes from this move, so it must become automatic.
- Step 2: The sign of a decides the openingThe graph of y = ax² + bx + c is a parabola whose opening is decided entirely by the sign of a: when a > 0 it opens upward like a bowl and the vertex is the minimum of the whole function; when a < 0 it opens downward like an umbrella and the vertex is the maximum. In y = -3x² + 2x - 1 we have a = -3 < 0, so the parabola opens downward and the vertex is a maximum point. Also, the larger the absolute value of a, the narrower the parabola, which is useful when comparing two curves.
- Step 3: The vertex formula and extreme valuesThe x-coordinate of the vertex has a fixed formula, x = -b/(2a); substituting this x into the function gives the y-coordinate. For y = x² - 6x + 5: x = -(-6)/(2 × 1) = 3 and y = 9 - 18 + 5 = -4, so the vertex is (3, -4), which is also the minimum of the whole function. When an application asks for the minimum cost, maximum profit or greatest height, the answer is this y-value of the vertex; after finding it, check the sign of a to state whether it is a maximum or a minimum, not just the coordinates.
- Step 4: The discriminant predicts x-interceptsThe discriminant Δ = b² - 4ac decides how the parabola meets the x-axis: Δ > 0 gives two intercepts, Δ = 0 gives exactly one (the parabola is tangent to the axis), and Δ < 0 gives none, with the whole curve above or below the axis. For y = x² + 2x + 5, Δ = 2² - 4 × 1 × 5 = -16 < 0, so the graph never touches the x-axis. Computing the discriminant before sketching prevents drawing a picture that contradicts the facts, and it is the first check of any rough graph.
- Step 5: Rules for transforming graphsBasic parabolas such as y = x² follow fixed rules under transformation: f(x) + k shifts the whole curve up k units, or down when k is negative; f(x - h) shifts right h units, because x must be h larger to give the same output, and this is the rule most often remembered backwards; -f(x) flips the graph vertically and reverses the opening. For example y = (x - 2)² + 1 is y = x² shifted right 2 units and up 1 unit, moving the vertex from the origin to (2, 1), which can be read off directly.
- Step 6: A three-step framework for describing parabolasDescribe a quadratic graph in a fixed order to cover every scoring point: first the direction of opening, decided by the sign of a; second the vertex and the axis of symmetry, which is the line x = -b/(2a); third the intercepts, with the y-intercept at (0, c) and the number of x-intercepts decided by the discriminant. With all three parts complete, a description question has a full framework, no available mark is missed, and the examiner can see every key point at a glance.
4Diagrams Diagrams
5Worked example Example
Sample: find the direction of opening, the vertex and the maximum of y = -2x² + 8x + 1, and decide the number of x-intercepts.
- Step 1: Since a = -2 < 0, the parabola opens downward like an umbrella, so the vertex is the highest point of the whole graph and the function has a maximum but no minimum.
- Step 2: The x-coordinate of the vertex is x = -b/(2a) = -8/(2 × (-2)) = 2; handle the negative denominator carefully, and the axis of symmetry is the line x = 2.
- Step 3: Substitute x = 2 to find the y-coordinate: y = -2 × 2² + 8 × 2 + 1 = -8 + 16 + 1 = 9, so the vertex is (2, 9), and this y-value is also the maximum of the function.
- Step 4: Compute the discriminant: Δ = 8² - 4 × (-2) × 1 = 64 + 8 = 72 > 0, so the parabola has two x-intercepts, and the sketch should show a downward curve crossing the x-axis twice.
- Answer: Conclusion: since a = -2 < 0 the parabola opens downward; the vertex is (2, 9) with maximum value 9; the axis of symmetry is the line x = 2; and Δ = 72 > 0 gives two x-intercepts. Fix the answering order as opening first, vertex second, discriminant last: each of the three parts matches one scoring point in a description question, and writing them all avoids lost marks. If the question goes on to ask where the function increases or decreases, use the axis x = 2: the function increases to the left of the axis and decreases to the right, a fixed property of a downward-opening parabola.
6Common mistakes Mistakes
7Quick check Quick check
Q1The condition for y=ax²+bx+c to open downward?
Q2The x-coordinate of the vertex?
Q3When Δ=0, how does the graph meet the x-axis?
Q4How does y=f(x)+3 transform the graph?
Q5The minimum value of y=x²-6x+5?
8Recap Recap
- f(x) is substitution: bracket negatives.
- Opening follows a: positive up, negative down.
- Vertex (-b2a, f(-b2a)) answers all max-min questions.
- Δ predicts intercepts: two, one, none.
- Transformations: +k up, -h right, minus flips.