函數與圖像:二次函數的模樣

Intermediate

Function notation, parabola features and discriminants: the three codes of quadratic graphs.

For:S4 Mathematics · Unit:Number & algebra · Lesson 9 of 10 in the learning path

After this lesson, you can:
  • f(x) is substitution: bracket negatives.
  • Opening follows a: positive up, negative down.
  • Vertex (-b2a, f(-b2a)) answers all max-min questions.
文體:數學原理講解(自撰教材)

文體小知識:函數與圖像——對應 DSE 核心單元「函數及圖像」:由代入求值到二次函數圖像,是 DSE 卷二高頻考點。

數學Mathematics

1Summary 重點摘要

Function notation, parabola features and discriminants: the three codes of quadratic graphs.

2Vocabulary cards Vocabulary

F
Function函數

A rule mapping each x to one output f(x).

P
Parabola拋物線

The U-shaped graph of a quadratic.

V
Vertex頂點

The maximum or minimum point.

D
Discriminant判別式

Δ=b²-4ac: predicts x-intercepts.

A
Axis of symmetry對稱軸

The vertical line through the vertex.

x
x-interceptx 軸截距

Where the graph crosses the x-axis.

T
Transformation圖像變換

Shifting or flipping a graph.

M
Maximum value最大值

The y-value at the vertex when a<0.

3Step by step Steps

  1. Step 1: The notation f(x) is substitutionThe notation f(x) means: take the value inside the brackets and put it in place of x on the right-hand side. For f(x) = 2x - 3, we get f(4) = 2 × 4 - 3 = 5 and f(-1) = 2 × (-1) - 3 = -5. For f(x) = x² + 1, finding f(-2) requires writing (-2)² + 1 = 5 with brackets around the negative number, otherwise it is easily miscalculated as -4. Substitution underpins everything about functions; every point (c, f(c)) on the graph comes from this move, so it must become automatic.
  2. Step 2: The sign of a decides the openingThe graph of y = ax² + bx + c is a parabola whose opening is decided entirely by the sign of a: when a > 0 it opens upward like a bowl and the vertex is the minimum of the whole function; when a < 0 it opens downward like an umbrella and the vertex is the maximum. In y = -3x² + 2x - 1 we have a = -3 < 0, so the parabola opens downward and the vertex is a maximum point. Also, the larger the absolute value of a, the narrower the parabola, which is useful when comparing two curves.
  3. Step 3: The vertex formula and extreme valuesThe x-coordinate of the vertex has a fixed formula, x = -b/(2a); substituting this x into the function gives the y-coordinate. For y = x² - 6x + 5: x = -(-6)/(2 × 1) = 3 and y = 9 - 18 + 5 = -4, so the vertex is (3, -4), which is also the minimum of the whole function. When an application asks for the minimum cost, maximum profit or greatest height, the answer is this y-value of the vertex; after finding it, check the sign of a to state whether it is a maximum or a minimum, not just the coordinates.
  4. Step 4: The discriminant predicts x-interceptsThe discriminant Δ = b² - 4ac decides how the parabola meets the x-axis: Δ > 0 gives two intercepts, Δ = 0 gives exactly one (the parabola is tangent to the axis), and Δ < 0 gives none, with the whole curve above or below the axis. For y = x² + 2x + 5, Δ = 2² - 4 × 1 × 5 = -16 < 0, so the graph never touches the x-axis. Computing the discriminant before sketching prevents drawing a picture that contradicts the facts, and it is the first check of any rough graph.
  5. Step 5: Rules for transforming graphsBasic parabolas such as y = x² follow fixed rules under transformation: f(x) + k shifts the whole curve up k units, or down when k is negative; f(x - h) shifts right h units, because x must be h larger to give the same output, and this is the rule most often remembered backwards; -f(x) flips the graph vertically and reverses the opening. For example y = (x - 2)² + 1 is y = x² shifted right 2 units and up 1 unit, moving the vertex from the origin to (2, 1), which can be read off directly.
  6. Step 6: A three-step framework for describing parabolasDescribe a quadratic graph in a fixed order to cover every scoring point: first the direction of opening, decided by the sign of a; second the vertex and the axis of symmetry, which is the line x = -b/(2a); third the intercepts, with the y-intercept at (0, c) and the number of x-intercepts decided by the discriminant. With all three parts complete, a description question has a full framework, no available mark is missed, and the examiner can see every key point at a glance.

4Diagrams Diagrams

二次函數的模樣:開口・頂點・對稱軸a > 0 開口向上有最低點a < 0 開口向下有最高點對稱軸對稱軸頂點 x 坐標 = −b/2a | y = a(x−h)²+k 頂點就係 (h, k)應用:拋物線搵最大利潤·最高拋射點——現實優化問題嘅數學模型
Fig. 1: Quadratic function shapes

5Worked example Example

Sample: find the direction of opening, the vertex and the maximum of y = -2x² + 8x + 1, and decide the number of x-intercepts.

  1. Step 1: Since a = -2 < 0, the parabola opens downward like an umbrella, so the vertex is the highest point of the whole graph and the function has a maximum but no minimum.
  2. Step 2: The x-coordinate of the vertex is x = -b/(2a) = -8/(2 × (-2)) = 2; handle the negative denominator carefully, and the axis of symmetry is the line x = 2.
  3. Step 3: Substitute x = 2 to find the y-coordinate: y = -2 × 2² + 8 × 2 + 1 = -8 + 16 + 1 = 9, so the vertex is (2, 9), and this y-value is also the maximum of the function.
  4. Step 4: Compute the discriminant: Δ = 8² - 4 × (-2) × 1 = 64 + 8 = 72 > 0, so the parabola has two x-intercepts, and the sketch should show a downward curve crossing the x-axis twice.
  5. Answer: Conclusion: since a = -2 < 0 the parabola opens downward; the vertex is (2, 9) with maximum value 9; the axis of symmetry is the line x = 2; and Δ = 72 > 0 gives two x-intercepts. Fix the answering order as opening first, vertex second, discriminant last: each of the three parts matches one scoring point in a description question, and writing them all avoids lost marks. If the question goes on to ask where the function increases or decreases, use the axis x = 2: the function increases to the left of the axis and decreases to the right, a fixed property of a downward-opening parabola.

6Common mistakes Mistakes

✗ Substituting negatives without brackets: f(-2)=2×-2².
✓ f(-2)=2(-2)²=2(4)=8 — square first, brackets are essential.
✗ Reversing the vertex formula to x=b2a.
✓ It is x=-b2a — check with y=x²-6x+5, whose vertex sits at x=3.
✗ Believing f(x-h) shifts the graph left.
✓ f(x-h) shifts right; sketching verifies it fastest.
✗ Treating Δ<0 as an error.
✓ Δ<0 is normal: the graph misses the x-axis and the equation has no real roots.

7Quick check Quick check

Q1The condition for y=ax²+bx+c to open downward?

Q2The x-coordinate of the vertex?

Q3When Δ=0, how does the graph meet the x-axis?

Q4How does y=f(x)+3 transform the graph?

Q5The minimum value of y=x²-6x+5?

8Recap Recap

  • f(x) is substitution: bracket negatives.
  • Opening follows a: positive up, negative down.
  • Vertex (-b2a, f(-b2a)) answers all max-min questions.
  • Δ predicts intercepts: two, one, none.
  • Transformations: +k up, -h right, minus flips.

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