Pythagoras' Theorem

Basic

Learn Pythagoras' theorem: square of longest side of right triangle equals sum of squares of other two sides.

For:Secondary 2 Mathematics · Unit:Pythagoras' theorem · Lesson 27 of 29 in the learning path

After this lesson, you can:
  • Only for right triangles
  • Hypotenuse always longest, opposite right angle
  • a² + b² = c²
數學Mathematics
Before this lesson you should know: Dividing Polynomials

1Summary 重點摘要

Learn Pythagoras' theorem: square of longest side of right triangle equals sum of squares of other two sides.

2Vocabulary cards Vocabulary

R
Right angle直角

90° angle.

R
Right triangle直角三角形

Triangle with one right angle.

H
Hypotenuse斜邊

Longest side opposite right angle.

L
Leg股

Two sides forming right angle.

S
Square平方

Multiply by itself.

S
Square root平方根

Reverse of square.

T
Theorem定理

Proven rule.

P
Pythagoras畢氏

Ancient Greek mathematician.

3Step by step Steps

  1. Step 1: The statement of the theoremPythagoras' theorem is among the most famous results in geometry: in a right triangle, the square of the hypotenuse, the longest side opposite the right angle, equals the sum of the squares of the two legs, that is a² + b² = c², where c is the hypotenuse and a, b are the legs. For legs 3 and 4, the hypotenuse is 5 since 3² + 4² = 5². Why only right triangles? The theorem describes exactly the side relation created by the right angle. A common mistake is placing the hypotenuse wrongly, writing a² + c² = b².
  2. Step 2: Identifying the hypotenuseBefore applying the theorem, identify the hypotenuse: it is always the side opposite the right angle and the longest side of the triangle. If the right angle is at vertex C, the hypotenuse is AB; if the right-angle mark sits at another vertex, the hypotenuse changes accordingly. Why does this matter? Once c is misplaced, every later addition and subtraction is wrong. Two checks: find the side facing the right-angle mark, or take the longest of the three sides. A common mistake is choosing c without looking at the right angle, especially when it is not in the usual position.
  3. Step 3: Finding the hypotenuseGiven the two legs, use c² = a² + b² and take the square root. For a = 3 and b = 4: c² = 9 + 16 = 25, so c = √25 = 5, the classic 3-4-5 triangle; for a = 6 and b = 8, c² = 36 + 64 = 100 and c = 10. Why take only the positive root? A side length is a distance and must be positive. A common mistake is adding the sides without squaring, writing c = 3 + 4 = 7; the correct answer is 5, and the difference is large.
  4. Step 4: Finding a legGiven the hypotenuse and one leg, rearrange the formula to b² = c² − a². For c = 5 and a = 3: b² = 25 − 9 = 16, so b = 4; for c = 13 and a = 5, b² = 169 − 25 = 144 and b = 12. Why subtract rather than add? The square of the hypotenuse is the largest, so the known leg's square is deducted from it to find the other leg. A common mistake is reversing the order, giving a² − c², a negative result; a negative value signals that the roles of the sides were mixed up.
  5. Step 5: Pythagorean triplesCertain integer triples satisfy a² + b² = c² exactly; they are called Pythagorean triples, and memorising the common ones speeds up calculation greatly: 3-4-5, 5-12-13, 8-15-17, 7-24-25. Multiplying a triple by any whole number gives another, for example twice 3-4-5 is 6-8-10, three times is 9-12-15, five times is 15-20-25. Why are they helpful? Examinations use them constantly; recognising 12 and 13 immediately gives the third side 5. A common mistake is grinding through square roots, or misremembering 5-12-13 as 5-12-15.
  6. Step 6: Limits of useTwo restrictions govern the theorem: first, it applies only to right triangles, never to acute or obtuse ones, so a triangle with sides 2, 3, 4, which is not right-angled, cannot be solved with a² + b² = c²; second, take only the positive square root, because lengths cannot be negative. Why stress the first point? Examinations often supply non-right triangles to tempt students into applying the theorem. The converse of the theorem can first confirm whether the angle is right. A common mistake is computing for every triangle; confirm the right angle before answering.

4Diagrams Diagrams

畢氏定理 a² + b² = c²Pythagoras: 3² + 4² = 5²a²3²=9b²4²=16c²5²=259 + 16 = 25a² + b² = c²兩個正方形嘅面積加埋啱啱等於斜邊嘅正方形a = 3b = 4
Fig. 1: Pythagoras squares

5Worked example Example

Example: The two legs of a right triangle are 6 and 8; find the hypotenuse.

  1. Step 1: Confirm the conditions: the triangle is right-angled, 6 and 8 are the legs, and the hypotenuse is c.
  2. Step 2: Write the formula: c² = a² + b² with a = 6 and b = 8.
  3. Step 3: Substitute and compute: c² = 6² + 8² = 36 + 64 = 100.
  4. Step 4: Take the square root: c = √100 = 10, the positive root only, since lengths are positive.
  5. Step 5: Check: 6² + 8² = 100 = 10², and 6-8-10 is the 3-4-5 triple doubled, consistent.
  6. Answer: 10. Model solution: in a right triangle c² = a² + b²; substituting a = 6 and b = 8 gives c² = 36 + 64 = 100, and taking the root gives c = 10. To find the hypotenuse, add the squares of the legs and take the square root; the check shows 6-8-10 is exactly twice the Pythagorean triple 3-4-5. State the formula, the substitution and the square root in the working.

6Common mistakes Mistakes

✗ Using on non-right triangle
✓ Wrong! Must be right triangle to use!
✗ Misidentifying hypotenuse
✓ Wrong! Hypotenuse is always longest side! Always opposite right angle!
✗ Adding sides directly instead of squares
✓ Wrong! It's square plus square, then square root! Not adding side lengths directly!
✗ Forgetting to take square root
✓ Wrong! After calculating a² + b², must take square root to get answer!

7Quick check Quick check

Q1Pythagoras' formula?

Q2Hypotenuse is?

Q33-4-5 triangle hypotenuse?

Q4Pythagoras' theorem only works on?

Q5After calculating sum of squares must?

8Recap Recap

  • Only for right triangles
  • Hypotenuse always longest, opposite right angle
  • a² + b² = c²
  • After calculating take square root
  • Common triples: 3-4-5, 5-12-13

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