Substitution & expansion

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Substitution = putting numbers into an expression; expansion = removing brackets with the distributive law. Master both and algebra flows.

For:Secondary 1 Mathematics · Unit:Introduction to algebra · Lesson 8 of 20 in the learning path

After this lesson, you can:
  • Substitute: replace variable with number
  • Distributive law: a(b+c) = ab + ac
  • With negative: watch signs
數學Mathematics
Before this lesson you should know: Introduction to algebraic expressions

1Summary 重點摘要

Substitution = putting numbers into an expression; expansion = removing brackets with the distributive law. Master both and algebra flows.

2Vocabulary cards Vocabulary

S
Substitution代入

Replace variable with number.

E
Expand展開

Remove brackets.

D
Distributive law分配律

a(b+c) = ab + ac.

B
Bracket括號

( ) grouping.

T
Term項

Parts separated by +/−.

C
Coefficient係數

Number in front of variable.

S
Simplify化簡

Combine like terms.

E
Expression代數式

Variables, constants, operators.

3Step by step Steps

  1. 1. Substitution: one variableSubstitution means replacing the variable with a concrete value, then calculating by the order of operations. Example: 3x + 2 when x = 4 — replace x with 4, giving 3(4) + 2 = 12 + 2 = 14. Two steps only: replace, then calculate. Note that 3(4) means 3 times 4, with the multiplication sign usually omitted. A common error is reading 3x + 2 as 34 + 2, gluing the digits together; the correct reading is 3 times x, then add 2. Writing out each step keeps substitution marks safe.
  2. 2. Substitution: two variablesTwo variables substitute the same way — each takes its own value. Example: 2x + 3y when x = 1 and y = 2 — replace x with 1 and y with 2, giving 2(1) + 3(2) = 2 + 6 = 8. The point: every variable takes only its own value, never swapped. A common error is reading 2x as 21 when x = 1, or 3y as 32 when y = 2; the correct reading is always 'coefficient times the value'. Write brackets around each substituted value, e.g. 2(1) + 3(2) — vital when the value is negative.
  3. 3. Expand: single bracketExpansion uses the distributive law: the number outside the bracket multiplies every term inside. Example: 3(x + 2) = 3 × x + 3 × 2 = 3x + 6. The point: the outside number multiplies every term, not just the first. A life view: each gift costs 3 dollars, take x of them plus 2 more, and the total is 3x + 6 dollars. A common error is multiplying only the first term, writing 3(x + 2) as 3x + 2; a check: after expansion the number of terms should match the inside — two terms in, two terms out.
  4. 4. Expand: with negativeWhen a negative sits outside the bracket, its sign travels with every term. Example: −2(x − 3) = (−2) × x + (−2) × (−3) = −2x + 6; note (−2) × (−3) gives +6, since two minuses make a plus. Two common errors: writing −2(x − 3) as −2x − 6, forgetting that negative times negative is positive; and multiplying only the first term by −2. A check: substitute a number — at x = 1 the original gives −2(1 − 3) = −2 × (−2) = 4, while the expansion gives −2(1) + 6 = 4; matching values mean the work is right.
  5. 5. Expand then simplifyWith two brackets, expand each first, then collect like terms. Example: 3(x + 2) + 2(x − 1) = 3x + 6 + 2x − 2. Collecting: x terms go together, 3x + 2x = 5x; constants go together, 6 + (−2) = 4; the answer is 5x + 4. Common errors: expanding 2(x − 1) as 2x − 1, missing the second term; or mishandling the sign in 6 + (−2). A good habit: after expanding, copy the whole expression once, circle the x terms and the constants separately, then collect each group — the order shows itself.
  6. 6. Simplify first then substituteEvaluation offers two roads. Example: 3(x + 2) when x = 1. Method one, substitute directly: 3(1 + 2) = 3(3) = 9. Method two, expand first then substitute: 3x + 6 = 3(1) + 6 = 9. The answers agree, because the expression is equivalent before and after expansion. When the expression is complicated, simplifying first is usually faster and safer, since the number of multiplications drops. A common error is forgetting to compute inside the bracket first — 1 + 2 comes before multiplying; brackets first is the first rule of the order of operations.
  7. 7. ApplicationA geometry application: a rectangle's length is (x + 2) cm and its width is x cm — what is the perimeter? Perimeter = 2 × (length + width) = 2[(x + 2) + x] = 2(2x + 2) = 4x + 4 cm. If x = 5, the perimeter is 4(5) + 4 = 24 cm; then the length is 7 and the width 5, and 2(7 + 5) = 24 checks out. A common error is adding length and width once and stopping, forgetting the factor 2; remember, a perimeter is the total of four sides.

4Diagrams Diagrams

代入:把字母換成數 Substitutiona = 4已知 given3a + 2公式 expression= ?要求 find3a + 2 → 3 × 4 + 2 → 12 + 2 = 14三步:寫低已知 → 換走字母 → 跟「先乘除後加減」次序計易錯位:3a 係 3 × a 唔係「三百幾」;代負數要加括號:a=−2 → 3×(−2)
Fig. 1: Substitution

5Worked example Example

Example: when x = 2, find the value of 3(x + 4) − 2x.

  1. Expand first: 3(x + 4) = 3x + 12, so the expression becomes 3x + 12 − 2x.
  2. Collect like terms: 3x − 2x = x, so the expression simplifies to x + 12.
  3. Substitute x = 2: x + 12 = 2 + 12 = 14.
  4. Check with the original: 3(2 + 4) − 2(2) = 3 × 6 − 4 = 18 − 4 = 14, matching the answer.
  5. Compare the two roads: direct substitution needs 3 × 6 and then minus 4; simplify-then-substitute needs one addition — faster and safer.
  6. Answer: The answer is 14. Expand 3(x + 4) to 3x + 12, collect like terms to get x + 12, substitute x = 2 to get 14; the original expression checks out: 3(2 + 4) − 2(2) = 14. Simplify first, substitute second — the least work and the safest route.

6Common mistakes Mistakes

✗ 3(x + 2) = 3x + 2 (forget constant).
✓ Distributive: 3x + 6.
✗ −2(x − 3) = −2x − 6 (sign wrong).
✓ −2x + 6 (negative × negative = positive).
✗ After expanding, no combining.
✓ Always combine like terms.
✗ No brackets when substituting.
✓ Use brackets: 3(4) + 2, not 34 + 2.

7Quick check Quick check

Q13x + 2 when x = 4 = ?

Q22x + 3y when x=1, y=2 = ?

Q33(x + 2) = ?

Q4−2(x − 3) = ?

Q53(x + 2) + 2(x − 1) = ?

8Recap Recap

  • Substitute: replace variable with number
  • Distributive law: a(b+c) = ab + ac
  • With negative: watch signs
  • After expanding, combine like terms
  • Simplify first can be faster

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