Introduction to algebraic expressions
FoundationLetters stand for numbers: one expression describes every case. Only like terms combine, and the × sign usually disappears.
After this lesson, you can:
- Variable: letter for unknown
- Coefficient: number in front of variable
- Like terms: same variable to combine
Before this lesson you should know: Place value & the four operations
1Summary 重點摘要
Letters stand for numbers: one expression describes every case. Only like terms combine, and the × sign usually disappears.
2Vocabulary cards Vocabulary
V
Variable變數
Letter representing unknown number.
C
Constant常數
Fixed number.
C
Coefficient係數
Number in front of variable.
T
Term項
Parts separated by +/−.
E
Expression代數式
Combination of variables, constants, operators.
L
Like terms同類項
Same variable.
S
Substitution代入
Replace variable with number.
E
Evaluate求值
Calculate the value.
3Step by step Steps
- 1. What is an algebraic expression?An algebraic expression is a mathematical phrase made of numbers, letters (variables) and operation signs, describing how quantities relate. Take 3x + 2: x is the variable, standing for an unknown number that can change; 3 is the coefficient, the number in front of x; 2 is the constant, whose value never changes. The great advantage is that one short expression covers a whole family of problems: 3x + 2 can mean '3 pens plus 2 dollars' or '3 bags of sweets plus 2 pieces', without writing a new sum for every situation. This is the key step from arithmetic into algebra.
- 2. What is a variable?A variable is a letter standing for a number that can take different values. In 3x + 2y, both x and y are variables, each free to be any number. When x = 1 and y = 2, 3x + 2y = 3(1) + 2(2) = 3 + 4 = 7; when x = 5 and y = 0, the same expression becomes 3(5) + 2(0) = 15. So one expression gives different results as the variables change — exactly why they are called variables. Note: within one expression the same letter always means the same number, and different letters may stand for different numbers; mixing them up is a sure way to go wrong.
- 3. SubstitutionSubstitution means replacing each variable with a concrete number, then working out the value in the correct order of operations. For 3x + 2 when x = 4: replace x with 4, giving 3(4) + 2; multiply first, 3 × 4 = 12, then add the constant, 12 + 2 = 14. So when x = 4, the value of 3x + 2 is 14. One more practice: when x = −2, 3(−2) + 2 = −6 + 2 = −4. A common mistake is dropping the brackets and turning 3(−2) into 3 − 2 = 1, a completely different answer; writing the brackets first, then calculating, avoids this slip.
- 4. Like termsLike terms are terms whose letter parts are identical; only like terms can be combined. For 3x + 5x, both terms contain x, so they are like terms and combine: 3x + 5x = (3 + 5)x = 8x. But in 3x + 2y the letter parts differ (one is x, the other y), so they are not like terms and cannot be merged into 5xy or anything else — they simply stay as they are. A daily-life picture helps: 3 apples plus 5 apples makes 8 apples, but 3 apples plus 2 bananas remain 3 apples and 2 bananas, never '5 apple-bananas'. Constants (such as 2 and 7) are like terms with each other and can be combined.
- 5. Addition and subtractionTo simplify addition and subtraction with brackets: first remove the brackets, then combine like terms. For (3x + 2) + (5x − 1): the sign before the second bracket is plus, so just drop the brackets, giving 3x + 2 + 5x − 1; combine the x terms, 3x + 5x = 8x; combine the constants, 2 + (−1) = 1; the result is 8x + 1. A trickier case: (3x + 2) − (5x − 1). The minus sign flips every term inside the second bracket: 3x + 2 − 5x + 1 = −2x + 3. The most common error is forgetting to flip the signs, writing −(5x − 1) as −5x − 1; subtracting a bracket changes the sign of every term inside it.
- 6. MultiplicationMultiplication relies on the distributive law: the factor outside the bracket multiplies every term inside. For 3(x + 2): 3 times x gives 3x, and 3 times 2 gives 6, so 3(x + 2) = 3x + 6. If the outside factor is negative or a variable, the method is the same: −2(x − 4) = −2x + 8 (note that −2 × −4 = +8), and x(x + 5) = x² + 5x. Two mistakes appear most often: multiplying only the first term, writing 3(x + 2) as 3x + 2 and missing the 2; and mishandling the negative sign, writing −2(x − 4) as −2x − 8. After expanding, check that the number of terms matches the number inside the bracket — a quick and effective self-check.
- 7. SimplifyCombining all the techniques above lets you handle longer expressions. For 5x + 3 + 2x − 1: first identify the like terms — the x terms are 5x and 2x, combining to 7x; the constants are 3 and −1, combining to 2; the result is 7x + 2. Slightly harder: 2(x + 3) + 3(x − 1) = 2x + 6 + 3x − 3 = 5x + 3. Build a fixed routine: remove brackets, mark like terms, combine them, then check that nothing is missing. Writing the answer in order (such as 7x + 2) keeps it clear, easy for teachers to mark and easy to revise later.
- 8. Common mistakes summaryWhen working with algebraic expressions, avoid four frequent errors. First, combining unlike terms, such as turning 3x + 2y into 5xy — terms with different letters never combine. Second, substituting negative numbers without brackets: putting x = −3 into x² and writing −3² = −9; it should be (−3)² = 9. Third, multiplying only the first term when expanding, as in 3(x + 2) where the 2 is missed. Fourth, confusing coefficients with powers, thinking x + x = x²; in fact x + x = 2x, while x × x = x². After each question, test with a simple number (say x = 1) in both the original and the simplified expression: they match only when the simplification is correct. This habit saves many careless marks.
4Diagrams Diagrams
5Worked example Example
Example: simplify 3x + 5 − x + 2.
- List all terms: 3x, +5, −x, +2
- Combine the x terms: 3x − x = 2x
- Combine the constants: 5 + 2 = 7
- Write the result: 2x + 7
- Check with x = 1: original 3 + 5 − 1 + 2 = 9; new 2(1) + 7 = 9 ✓
- Answer: 2x + 7 — only like terms combine: x terms together, numbers together.
6Common mistakes Mistakes
✗ 3x + 2y = 5xy (combine different variables).
✓ Different variables: leave as 3x + 2y.
✗ 3(x + 2) = 3x + 2 (forget constant).
✓ Distributive: 3(x + 2) = 3x + 6.
✗ 5x + 3 + 2x = 10x (add everything).
✓ Like terms only: 7x + 3.
✗ x is multiplication sign.
✓ x is variable (multiplication uses × or omit).
7Quick check Quick check
Q13x + 2 when x = 4 = ?
Answer: 14.
Did you get it right?
Q23x + 5x = ?
Answer: 8x.
Did you get it right?
Q3(3x + 2) + (5x − 1) = ?
Answer: 8x + 1.
Did you get it right?
Q43(x + 2) = ?
Answer: 3x + 6.
Did you get it right?
Q55x + 3 + 2x − 1 = ?
Answer: 7x + 2.
Did you get it right?
8Recap Recap
- Variable: letter for unknown
- Coefficient: number in front of variable
- Like terms: same variable to combine
- Substitution: replace variable with number
- Distributive law: 3(x+2) = 3x + 6