Lesson 30: Solving Equations Practice
BasicFour basic types: x+a=b, x-a=b, ax=b, x÷a=b. Practice each type, learn to isolate x.
After this lesson, you can:
- Goal: isolate x
- x + a = b: subtract a
- x - a = b: add a
文體小知識:加減乘除各類方程
Before this lesson you should know: Lesson 29: What is an Equation?
§Text Passage
1Goal of solving: isolate x on one side, number on other. Method: do same operation both sides, cancel the number next to x.
2Four basic types: 1) x + a = b (subtract a); 2) x - a = b (add a); 3) a x = b (divide a); 4) x ÷ a = b (multiply a).
3After each question, check: substitute x answer back into original, see if both sides equal.
1Summary 重點摘要
Four basic types: x+a=b, x-a=b, ax=b, x÷a=b. Practice each type, learn to isolate x.
2Vocabulary cards Vocabulary
s
solve動詞
Solve
i
isolate動詞
Isolate
s
substitute動詞
Substitute
c
check動詞
Check
u
unknown名詞
Unknown
e
equation名詞
Equation
b
both sides名詞
Both sides
o
operation名詞
Operation
3Step by step Steps
- Block 1: Type 1: x + a = bExample: x + 7 = 15. Since 7 is added to x, subtract 7 from both sides: on the left, +7 and -7 cancel, leaving x; on the right, 15 - 7 = 8, so x = 8. Check: 8 + 7 = 15 matches, so the solution is correct. Addition equations are solved with subtraction. Another example: x + 3.2 = 9 — subtract 3.2 from both sides, x = 9 - 3.2 = 5.8; the aim of moving terms is to leave x alone on one side and gather all the numbers on the other.
- Block 2: Type 2: x - a = bExample: x - 5 = 11. Since 5 is subtracted from x, add 5 to both sides: on the left, -5 and +5 cancel, leaving x; on the right, 11 + 5 = 16, so x = 16. Check: 16 - 5 = 11 matches. Subtraction equations are solved with addition, the opposite of type one. Another example: x - 12 = 7.5 — add 12 to both sides, x = 7.5 + 12 = 19.5; check 19.5 - 12 = 7.5. Whole numbers or decimals, the idea of cancelling is exactly the same.
- Block 3: Type 3: ax = bExample: 3x = 18, meaning x multiplied by 3. Divide both sides by 3: on the left, 3x ÷ 3 leaves x; on the right, 18 ÷ 3 = 6, so x = 6. Check: 3 × 6 = 18, both sides equal. Multiplication equations are solved with division, and 3x means 3 × x. Another example: 6x = 4.8 — divide both sides by 6, x = 4.8 ÷ 6 = 0.8; check 6 × 0.8 = 4.8. Whatever the coefficient is, divide by it — the goal is always to make x's coefficient 1.
- Block 4: Type 4: x ÷ a = bExample: x ÷ 4 = 5, meaning x divided by 4. Multiply both sides by 4: on the left, ÷4 and ×4 cancel, leaving x; on the right, 5 × 4 = 20, so x = 20. Check: 20 ÷ 4 = 5 matches. Division equations are solved with multiplication. Another example: x ÷ 2.5 = 4 — multiply both sides by 2.5, x = 4 × 2.5 = 10; check 10 ÷ 2.5 = 4. All four types share one principle: always do the same thing to both sides.
- Block 5: Decimals TooDecimals can appear in equations too, and the method does not change. Example: x + 2.5 = 6; subtract 2.5 from both sides, and the right becomes 6 - 2.5 = 3.5, so x = 3.5. Check: 3.5 + 2.5 = 6, correct. Line up the decimal points when working out the arithmetic; the rest is the same as whole-number equations. Another example: x - 1.8 = 4.2 — add 1.8 to both sides, x = 4.2 + 1.8 = 6; check 6 - 1.8 = 4.2. Decimal addition and subtraction slip easily, so column form is the safest.
- Block 6: Fractions TooFractions can appear as well. Example: x + 12 = 34; subtract 12 from both sides, giving x = 34 - 12. Make the denominators the same first: 12 = 24, so x = 34 - 24 = 14. Check: 14 + 24 = 34, correct. With fractions, rewrite them over a common denominator before subtracting. Another example: x - 14 = 12 — add 14 to both sides, x = 12 + 14 = 24 + 14 = 34; check 34 - 14 = 24 = 12, matching the original equation.
4Diagrams Diagrams
5Worked example Example
Example: Solve the equation 4x = 20.
- Step 1: set the goal — leave x alone on one side and remove the coefficient 4 in front of it.
- Step 2: x is multiplied by 4, so use the opposite operation and divide both sides by 4: 4x ÷ 4 = 20 ÷ 4.
- Step 3: tidy both sides — on the left, 4x ÷ 4 leaves x; on the right, 20 ÷ 4 = 5, so x = 5.
- Step 4: check by substituting 5 back: 4 × 5 = 20, both sides equal, so the solution is correct.
- Answer: Answer: x = 5. For the multiplication equation 4x = 20, apply the opposite operation, division, to both sides to clear the coefficient 4 and leave x on its own; substituting x = 5 back gives 4 × 5 = 20, which matches, so the whole process is complete and correct.
6Common mistakes Mistakes
✗ Subtract left only
✓ Same operation both sides
✗ Wrong operation
✓ Add ↔ subtract; multiply ↔ divide
✗ Don't check
✓ Substitute back to check
✗ Don't know decimals
✓ Decimals same method
7Quick check Quick check
Q1x + 5 = 12, x = ?
Answer: 7
Did you get it right?
Q2x - 8 = 3, x = ?
Answer: 11
Did you get it right?
Q35 x = 25, x = ?
Answer: 5
Did you get it right?
Q4x ÷ 3 = 7, x = ?
Answer: 21
Did you get it right?
Q5After solving, do what?
Answer: Check
Did you get it right?
8Recap Recap
- Goal: isolate x
- x + a = b: subtract a
- x - a = b: add a
- a x = b: divide a
- x ÷ a = b: multiply a