Lesson 31: Equation Word Problems

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Use equations to solve word problems: translate word problem into equation, solve for answer. Learn to turn life problems into maths.

For:Primary 6 Mathematics · Unit:Simple equations · Lesson 31 of 31 in the learning path

After this lesson, you can:
  • Word problem: set x → write equation → solve → check
  • Unknown = what the question asks
  • Shopping: total + change = paid
文體:方程應用有聲朗讀

文體小知識:用方程解應用題

數學Mathematics
Before this lesson you should know: Lesson 30: Solving Equations Practice

§Text Passage

1Equation word problems: translate life problems into equations, then solve. Advantage: don't need to think steps, just follow equation.

2Steps: 1) What's the question? 2) Let x be unknown; 3) Write equation based on problem; 4) Solve; 5) Check and answer.

3Common types: shopping change, sharing money, age problems, number problems.

1Summary 重點摘要

Use equations to solve word problems: translate word problem into equation, solve for answer. Learn to turn life problems into maths.

2Vocabulary cards Vocabulary

w
word problem名詞

Word problem

t
translate動詞

Translate

u
unknown名詞

Unknown

a
age名詞

Age

g
gift名詞

Gift

b
book名詞

Book

c
check動詞

Check

s
solve動詞

Solve

3Step by step Steps

  1. Block 1: Shopping ProblemExample: buy 2 books at $x each, pay $100 and receive $32 change — how much is each book? The relation 'cost of two books + change = money paid' gives 2x + 32 = 100. Subtract 32 from both sides for 2x = 68, then divide by 2 for x = 34, so each book is $34. Check: 34 × 2 = 68 and 68 + 32 = 100, matching the payment; the unknown could instead be the change — a different set-up should give the same answer, a good test of whether the equation is sound.
  2. Block 2: Sharing MoneyExample: 5 classmates buy a gift together, each contributing $x, and the gift costs $180 — how much each? The relation '5 shares = total price' gives 5x = 180. Dividing both sides by 5 gives x = 36, so each contributes $36. This type needs only one multiplication step. Check: 36 × 5 = 180, exactly the price of the gift; in any pooled-purchase question of 'x dollars each, n people in all', the equation is always n lots of x equal to the total — a fixed form.
  3. Block 3: Age ProblemExample: Dad is x years old this year, his son is 12, and Dad is 28 years older — how old is Dad? The relation 'Dad's age - son's age = the difference' gives x - 12 = 28. Adding 12 to both sides gives x = 40, so Dad is 40 this year. Check: 40 - 12 = 28, matching the given difference; age problems have one special feature — the difference between two ages never changes over the years, and this is often the key to the equation.
  4. Block 4: Number ProblemExample: a number multiplied by 3 and then increased by 5 equals 20 — what is the number? Let the number be x; 'times 3 plus 5' is written 3x + 5, so the equation is 3x + 5 = 20. Subtract 5 for 3x = 15, then divide by 3 for x = 5. The number is 5; checking, 3 × 5 + 5 = 20, correct. Name the unknown by translating the wording phrase by phrase: 'times 3' is written 3x, 'plus 5' is written + 5, and 'equals 20' is written = 20; matching phrase to phrase keeps the equation faithful.
  5. Block 5: How to Write?Turning a word problem into an equation takes three steps: first decide what the unknown is and call it x, such as the price of one book; second find the equal relation in the problem, such as two books plus change equaling the payment; third write the equation from that relation. A right relation is half the battle. Name the unknown after exactly what the question asks: if it asks the price of one book, let one book be x dollars, which makes both the equation and the check more direct. When hunting for the equal relation, watch words like 'in total', 'difference' and 'times as many' — they hint at adding, subtracting and multiplying.
  6. Block 6: Check ImportantAlways check after solving by putting the answer back into the story. Example: if each book is $34, two books are $68, and paying $100 returns $32 of change, matching the question exactly, so the solution is right. Checking catches a wrongly named unknown or a wrongly written equation — the final gate for word problems. Put the answer back into the story and recompute, rather than only re-checking the algebra: at $34 each, two books are $68, and $68 plus $32 change is exactly $100. With this habit, most slips are caught before you hand in.

4Diagrams Diagrams

文字題四步:設・列・解·答 Word problems in 4 steps1設let x be…2列write equation3解solve for x4答answer sentence例:哥哥比妹妹大 4 歲,兩人加埋 30 歲。設妹妹 x 歲 → x + (x+4) = 30→ 2x + 4 = 30 → x = 13 → 答:妹妹 13 歲,哥哥 17 歲(記得檢查!)最緊要第 4 步用文字答,仲要睇返題目問乜(問哥哥就答哥哥!)
Fig. 1: Word problems in 4 steps

5Worked example Example

Example: 3 classmates buy a $120 gift together. How much does each contribute?

  1. Step 1: name the unknown — let x be each person's share in dollars, the answer the question wants.
  2. Step 2: find the equal relation — the money from 3 people together equals $120, written as 3x = 120.
  3. Step 3: solve the equation by dividing both sides by 3, giving x = 120 ÷ 3 = 40.
  4. Step 4: check — 3 × 40 = 120 matches the price of the gift, so the solution is correct.
  5. Answer: Answer: each person contributes $40. The full routine for word problems is to name the unknown x, find the equal relation and write the equation, solve for x, and finally put the answer back into the situation to check; all four steps matter, and a matching check earns the final answer.

6Common mistakes Mistakes

✗ Calculate without x
✓ First set x as unknown
✗ Write equation wrong
✓ Follow problem statement
✗ Don't check
✓ Substitute back to check
✗ Answer doesn't answer question
✓ Answer what was asked

7Quick check Quick check

Q1First step of word problem?

Q22x = 50, x = ?

Q3Dad 25 years older than son, son 10, dad?

Q4After word problem, do what?

Q5Advantage of equation word problems?

8Recap Recap

  • Word problem: set x → write equation → solve → check
  • Unknown = what the question asks
  • Shopping: total + change = paid
  • Sharing: total = each × people
  • Always check

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