Equation of Circle

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Learn how to write equation of circle — given centre and radius.

For:Secondary 3 Mathematics · Unit:Coordinate geometry · Lesson 36 of 37 in the learning path

After this lesson, you can:
  • Standard form: (x - h)² + (y - k)² = r²
  • Centre (h, k), radius r
  • Centre at origin: x² + y² = r²
數學Mathematics
Before this lesson you should know: Coordinate Geometry: Straight Lines

1Summary 重點摘要

Learn how to write equation of circle — given centre and radius.

2Vocabulary cards Vocabulary

E
Equation of circle圓的方程

Represent circle using x and y

C
Centre圓心

Centre point of circle

R
Radius半徑

Distance from centre to circumference

(
(h, k)

Coordinates of centre

r
r

Symbol for radius

(
(x - h)² + (y - k)² = r²標準式

Standard form of circle equation

E
Expand展開

Multiply out the brackets

G
General form通式

Expanded form

3Step by step Steps

  1. Step 1: The standard formThe standard form of the circle with centre (h, k) and radius r is (x − h)² + (y − k)² = r². Why this shape? It comes directly from the definition of a circle: every point on the circle lies at distance r from the centre, so the distance formula gives √((x − h)² + (y − k)²) = r, and squaring both sides yields the standard form. For centre (2, 3) and radius 5, the equation is (x − 2)² + (y − 3)² = 25. A common mistake is writing the radius instead of its square on the right, or getting the signs of the coordinates wrong.
  2. Step 2: Writing the equation from centre and radiusGiven the centre and radius, substitute directly into the standard form. For centre (2, 3) and radius 5, the equation is (x − 2)² + (y − 3)² = 25; for centre (−1, 4) and radius 2, it is (x + 1)² + (y − 4)² = 4, where h = −1 turns x − h into x + 1. Why does a plus sign appear? Subtracting a negative number equals adding a positive one, and this sign change is the most error-prone spot. A common mistake is reading (x + 1)² as h = +1; remember the bracket is x minus the x-coordinate of the centre.
  3. Step 3: The special case of centre at the originIf the centre is the origin (0, 0), then h = k = 0 and the standard form simplifies to x² + y² = r². For example, a circle of radius 4 has equation x² + y² = 16, and the unit circle has x² + y² = 1. Why list this case separately? It is the simplest form of the standard equation, allows the equation to be written at once, and provides a quick check of answers. A common mistake is writing x² + y² = 4 for radius 4, forgetting the right side is 4² = 16; radius and squared radius must be kept distinct.
  4. Step 4: Expanding to the general formExpanding the standard form and collecting like terms gives the general form x² + y² + Dx + Ey + F = 0. Take (x − 2)² + (y − 3)² = 25: expansion gives x² − 4x + 4 + y² − 6y + 9 = 25. Why learn the expansion? Some questions supply the circle in general form and some demand the answer in general form, so the two must be interconvertible. Use the identity (a − b)² = a² − 2ab + b². A common mistake is dropping the middle terms, omitting −4x or −6y; another is forgetting the constant terms 4 and 9.
  5. Step 5: Simplifying to the general formContinuing: combine the constants on the left of x² − 4x + 4 + y² − 6y + 9 = 25, giving x² + y² − 4x − 6y + 13 = 25; move 25 to the left, giving x² + y² − 4x − 6y − 12 = 0, the general form with D = −4, E = −6 and F = −12. Why must the right side be 0? The general form is defined with all terms moved to one side and zero on the other. A common mistake is a sign error when moving terms, writing +12 instead of −12; substitute one point afterwards to verify.
  6. Step 6: Recovering the centre by completing the squareGiven the general form, use completing the square. For x² + y² − 4x − 6y − 12 = 0: move the constant to get x² − 4x + y² − 6y = 12; complete the square in x, x² − 4x = (x − 2)² − 4, and in y, y² − 6y = (y − 3)² − 9; substitute to get (x − 2)² − 4 + (y − 3)² − 9 = 12. Why subtract 4 and 9 back? Whatever is added while completing the square must be subtracted again to keep the equation balanced. A common mistake is forgetting to subtract the added constants, ruining the radius calculation.
  7. Step 7: The conclusion of the recoveryTidying the previous step: (x − 2)² + (y − 3)² = 12 + 4 + 9 = 25, the standard form, where the right side 25 is the squared radius, so radius = √25 = 5 and the centre is (2, 3). Check: this matches the equation written directly in Step 2 from the given centre and radius, confirming the algebra. Why practise both directions? Examinations test both, and reading the centre and radius from a general form is a common question. A common mistake is forgetting the square root, answering 25 as the radius; the radius is the positive square root.

5Worked example Example

Example: Write the equation of the circle with centre (−1, 2) and radius 3.

  1. Step 1: Write the standard form: (x − h)² + (y − k)² = r², where (h, k) is the centre and r the radius.
  2. Step 2: Identify the values: h = −1, k = 2 and r = 3.
  3. Step 3: Substitute into the standard form: (x − (−1))² + (y − 2)² = 3².
  4. Step 4: Simplify the signs: x − (−1) = x + 1 and 3² = 9, giving (x + 1)² + (y − 2)² = 9.
  5. Step 5: Check: the point (−1, 5) lies 3 units from the centre, and substituting gives 0² + 3² = 9, so the equation holds.
  6. Answer: (x + 1)² + (y − 2)² = 9. Model solution: the standard form is (x − h)² + (y − k)² = r²; substituting h = −1, k = 2 and r = 3 gives (x + 1)² + (y − 2)² = 9. Note that h = −1 turns x − h into x + 1, and the right side must be the squared radius 9, not 3; verify with a point 3 units from the centre.

6Common mistakes Mistakes

✗ Getting signs wrong when centre is negative
✓ When h = -1, x - (-1) = x + 1!
✗ Forgetting to square r
✓ Right side is r², not r!
✗ Mixing up x y position in centre (h, k)
✓ First coordinate is x (h), second is y (k)!
✗ Forgetting to move terms when expanding
✓ After expanding, move all constants to right side.

7Quick check Quick check

Q1Centre (0, 0), radius 4, equation?

Q2Centre (3, 0), radius 2, equation?

Q3Standard form of circle equation?

Q4Radius of x² + y² = 25?

Q5Centre of (x - 1)² + (y + 2)² = 9?

8Recap Recap

  • Standard form: (x - h)² + (y - k)² = r²
  • Centre (h, k), radius r
  • Centre at origin: x² + y² = r²
  • When h is negative, minus becomes plus
  • Complete the square on general form to find centre and radius

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