Coordinate Geometry: Straight Lines
AdvancedOn the coordinate plane: the distance between two points uses Pythagoras (distance formula), the slope = (y₂−y₁)/(x₂−x₁) measures steepness, and in the line equation y = mx + c, m is the slope and c is the y-intercept. These three tools plus Pythagoras are the core of S3 coordinate geometry.
- Coordinates: (x, y)
- Slope = (y₂−y₁)/(x₂−x₁)
- Line equation: y = mx + c (m slope, c y-intercept)
1Summary 重點摘要
On the coordinate plane: the distance between two points uses Pythagoras (distance formula), the slope = (y₂−y₁)/(x₂−x₁) measures steepness, and in the line equation y = mx + c, m is the slope and c is the y-intercept. These three tools plus Pythagoras are the core of S3 coordinate geometry.
2Vocabulary cards Vocabulary
Position on a plane as (x, y). e.g. (3, 2) means x=3, y=2.
Horizontal number line, positive to the right.
Vertical number line, positive upward.
How steep the line is. Slope = rise ÷ run = (y₂−y₁)/(x₂−x₁).
Where the line crosses y-axis. In y = mx + c, c is the y-intercept.
Formula for a line. Most common is y = mx + c.
(0, 0), where the two axes cross.
Flat line, slope = 0. e.g. y = 3.
3Step by step Steps
- Recapping the coordinate systemA position on the plane is fixed by coordinates (x, y): move x along the horizontal axis, right positive, then y along the vertical, up positive. Thus (3, 2) is 3 right and 2 up from the origin (0, 0) where the axes cross. Coordinate geometry's core idea is describing shapes by algebraic equations, turning figure questions into computations. This lesson studies the straight line: every point of one line satisfies the same linear equation in x and y — the line's identity card.
- The gradient formulaThe gradient measures steepness with m = (y₂ − y₁) ÷ (x₂ − x₁), vertical change over horizontal change. For the line through (1, 2) and (3, 6): y₂ − y₁ = 6 − 2 = 4 and x₂ − x₁ = 3 − 1 = 2, giving a gradient of 4 ÷ 2 = 2. The sign gives the direction: positive climbs, negative descends, zero is level. When substituting, subtract the two points' x and y in the same order: if y takes 'second minus first', x must too — inconsistent order flips the sign and misreads the direction.
- The line equation y = mx + cThe standard form is y = mx + c: m is the gradient and c the y-intercept, the height where the line crosses the y-axis. For y = 2x + 1, m = 2 and c = 1, crossing at (0, 1). The form's power: knowing m and c is knowing the whole line; conversely, reading a line's tilt and crossing gives back its equation. To test whether a point lies on the line, substitute its coordinates: a true statement means on the line, a false one means off it — a one-step verification.
- Writing the equation from two pointsGiven the line through (0, 1) and (2, 5): first the gradient m = (5 − 1) ÷ (2 − 0) = 4 ÷ 2 = 2; second, (0, 1) is itself the y-axis crossing, so c = 1, and the equation is y = 2x + 1. When neither point is the intercept, as with (1, 2) and (3, 6), find m = 2, then set the equation as y = 2x + c and substitute (1, 2): 2 = 2 + c, so c = 0 and the line is y = 2x. Verify with the other point before finishing, and the equation is safe.
- Horizontal and vertical linesOn a horizontal line every point shares one y, so the equation reads y = 3 and the gradient is 0; on a vertical line every point shares one x, so the equation reads x = 2 and the gradient is undefined, because the horizontal run is 0 and division by zero is impossible. The memory rule: y equals a number gives a horizontal line; x equals a number gives a vertical one. The standard error is swapping the two. Both special lines appear often in figure boundaries and simultaneous equations, so recognise them instantly.
- Distance between two points and combined useThe distance between A(x₁, y₁) and B(x₂, y₂) is AB = √[(x₂ − x₁)² + (y₂ − y₁)²], coming from Pythagoras: the horizontal and vertical differences are the two legs of a right triangle and AB is the hypotenuse. For A(1, 2) and B(4, 8): differences 3 and 6 give AB = √(9 + 36) = √45 = 3√5 ≈ 6.7. Combined coordinate-geometry questions often test slope, equation and length on the same line; proceed in the order slope, intercept, distance and the full marks follow steadily.
4Diagrams Diagrams
5Worked example Example
Example: A(1, 2) and B(4, 8); find the gradient of AB, its equation, and the length AB.
- Gradient: m = (8 − 2) ÷ (4 − 1) = 6 ÷ 3 = 2.
- Let the equation be y = 2x + c and substitute A(1, 2): 2 = 2 + c, so c = 0.
- The equation is y = 2x; check B(4, 8): 2 × 4 = 8, which holds.
- Distance: AB = √[(4 − 1)² + (8 − 2)²] = √(9 + 36) = √45.
- Simplify: √45 = √(9 × 5) = 3√5 ≈ 6.7.
- Summary: gradient 2, equation y = 2x, length 3√5 ≈ 6.7 — all three answers complete.
- Answer: m = 2, equation y = 2x and AB = 3√5 ≈ 6.7 — find m with the gradient formula, substitute a point for c to write the equation, then apply the distance formula and simplify the surd.
6Common mistakes Mistakes
7Quick check Quick check
Q1Line through (1, 2) and (3, 6), slope = ?
Q2y = 3x + 2 slope and y-intercept?
Q3Line through (0, 1) and (2, 5), equation = ?
Q4Is y = 4 horizontal or vertical?
Q5Line through (0, 3) and (2, 7), slope = ?
8Recap Recap
- Coordinates: (x, y)
- Slope = (y₂−y₁)/(x₂−x₁)
- Line equation: y = mx + c (m slope, c y-intercept)
- y = number = horizontal, x = number = vertical
- (0, c) is the y-intercept point