Special Angles

Basic

Sin, cos, tan of 30°, 45°, 60° are fixed values. Memorise them.

For:Secondary 3 Mathematics · Unit:Trigonometry · Lesson 19 of 37 in the learning path

After this lesson, you can:
  • Three special angles: 30°, 45°, 60°
  • Memorise sin, cos, tan values
  • Sin from small to big: 12, √22, √32
數學Mathematics
Before this lesson you should know: Trigonometric Ratios: sin, cos, tan

1Summary 重點摘要

Sin, cos, tan of 30°, 45°, 60° are fixed values. Memorise them.

2Vocabulary cards Vocabulary

S
Special angle特殊角

Three common angles: 30°, 45°, 60°.

S
Sin正弦

Opposite ÷ Hypotenuse.

C
Cos餘弦

Adjacent ÷ Hypotenuse.

T
Tan正切

Opposite ÷ Adjacent.

I
Isosceles triangle等腰三角形

Two sides equal, two base angles equal.

E
Equilateral triangle等邊三角形

All sides equal, all angles 60°.

R
Ratio比例

Comparison of two side lengths.

M
Memorise背熟

Must memorise, no need to calculate in exam.

3Step by step Steps

  1. Step 1: Why memorise special anglesThe sin, cos and tan of 30°, 45° and 60° are fixed values, used directly in exams without reaching for the calculator — fast, accurate, and exact rather than approximate. Example: for sin 30°, write 12 directly, which is more rigorous than the calculator's 0.5; some proofs can only continue with exact values. A common error is swapping the values between angles, e.g. writing sin 30° as √32; memorise the table and recite it regularly to stay safe.
  2. Step 2: Where 45° comes fromThe 45° values come from an isosceles right triangle: the two legs are equal, say 1 each, and by Pythagoras the hypotenuse = √(1² + 1²) = √2. Then sin 45° = opposite ÷ hypotenuse = 1/√2 = √22, cos 45° is also √22, and tan 45° = 1. Knowing the origin removes the need to memorise blindly: the two legs being equal forces sin and cos to be identical. A common error is in rationalising the denominator — 1/√2 multiplied above and below by √2 gives √22, not 2/√2.
  3. Step 3: Where 30° and 60° come fromThe 30° and 60° values come from cutting an equilateral triangle in half. Let the equilateral triangle have side 2; cutting along the height makes two right triangles with hypotenuse 2, short leg 1, and by Pythagoras the other leg = √(2² − 1²) = √3. Then sin 30° = 12, cos 30° = √32, tan 30° = 1/√3; and sin 60° = √32, cos 60° = 12, tan 60° = √3. Note how the sin and cos of 30° and 60° swap places. A common error is mixing the two angles' values; a sketch fixes the memory.
  4. Step 4: Memorise the tableThe full table: the 30° row is sin = 12, cos = √32, tan = 1/√3; the 45° row is sin = √22, cos = √22, tan = 1; the 60° row is sin = √32, cos = 12, tan = √3. To recite: write the three sin values first, get the cos row as the sin row reversed, then verify each tan cell as sin ÷ cos. Writing the table twice before the exam is enough. A common error is giving tan 30° as √3 — but √3 belongs to tan 60°.
  5. Step 5: How to memorise easilyThe memory trick: the three sin values from 30° to 60° are √12, √22, √32 — the numbers under the root climb 1, 2, 3; cos runs the same list in reverse, √32, √22, √12; and tan = sin ÷ cos can be computed on the spot whenever needed. The trick squeezes nine values into three lines and self-checks: for example, tan 45° = (√22) ÷ (√22) = 1, agreeing with the table. A common error is remembering cos in the same order as sin; remember 'cos reversed' instead.
  6. Step 6: How to useOn seeing 30°, 45° or 60°, substitute the exact value directly. Example: in a right triangle the side opposite the 30° angle is 5; find the hypotenuse. From sin 30° = opposite ÷ hypotenuse, 12 = 5 ÷ hypotenuse, so the hypotenuse = 5 ÷ (12) = 10. The steps: pick the right ratio (opposite and hypotenuse take sin), write the defining equation, then substitute the exact value and solve. A common error is choosing the wrong ratio, e.g. tan; a small sketch labelling opposite, adjacent and hypotenuse prevents it.

4Diagrams Diagrams

特殊角三角比:30°・45°・60° Special anglesθsincostan30°1/2√3/21/√345°√2/2√2/2160°√3/21/2√3兩個源頭:45° 等腰直角三角形(邊 1·1·√2)+ 30-60-90 三角形(1·√3·2)背法:sin 30°=½ 最易記;sin 由 ½ → √3/2 一路升;sin 同 cos 互為鏡像考試容許寫根式(√2/2)或小數(0.707)——睇題目要求
Fig. 1: Special angles

5Worked example Example

Example: in a right triangle, the side opposite the 45° angle is 3; find the hypotenuse.

  1. Confirm 45° is a special angle and write the exact value sin 45° = √22 — do not use the calculator's approximation.
  2. Write the definition: sin 45° = opposite ÷ hypotenuse, i.e. √22 = 3 ÷ hypotenuse.
  3. Solve: hypotenuse = 3 ÷ (√22) = 3 × 2/√2 = 6/√2.
  4. Rationalise the denominator: multiply above and below by √2 to get 6√22 = 3√2.
  5. Check: 3√2 ≈ 4.24, greater than the opposite side 3, as the hypotenuse must be the longest side — the answer is reasonable.
  6. Answer: The hypotenuse is 3√2. Working: from sin 45° = √22 and the opposite side 3, the equation √22 = 3 ÷ hypotenuse gives hypotenuse = 6/√2, which rationalises to 3√2. A numerical check shows 3√2 ≈ 4.24 exceeds 3, as the longest side should — the answer is correct.

6Common mistakes Mistakes

✗ Using calculator first
✓ Special angles: memorise answer directly, no calculator!
✗ Swapping sin and cos
✓ Remember: sin is opposite, cos is adjacent! Don't swap!
✗ Swapping 30° and 60°
✓ Remember: 30° opposite short side, so sin30° = 12 (smallest)!
✗ Forgetting tan = sin ÷ cos
✓ If you can't remember tan, calculate it as sin ÷ cos!

7Quick check Quick check

Q1sin30° = ?

Q2cos45° = ?

Q3tan60° = ?

Q4sin60° = ?

Q5tan45° = ?

8Recap Recap

  • Three special angles: 30°, 45°, 60°
  • Memorise sin, cos, tan values
  • Sin from small to big: 12, √22, √32
  • Cos reversed: √32, √22, 12
  • Tan = sin ÷ cos

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