Simultaneous Linear Equations

Basic

Two equations with two unknowns, solve for x and y by substitution or elimination.

For:Secondary 3 Mathematics · Unit:Number & algebra · Lesson 4 of 37 in the learning path

After this lesson, you can:
  • Simultaneous equations = 2 equations, 2 unknowns
  • Substitution: plug one into the other
  • Elimination: add/subtract to cancel one unknown
數學Mathematics

1Summary 重點摘要

Two equations with two unknowns, solve for x and y by substitution or elimination.

2Vocabulary cards Vocabulary

S
Simultaneous equations聯立方程

Two or more equations with the same unknowns.

U
Unknown未知數

Variables to find, usually x and y.

S
Substitution method代入法

Putting one equation into another.

E
Elimination method消元法

Adding/subtracting both to cancel one unknown.

S
Solution解

The (x, y) pair that satisfies all equations.

L
Linear equation一次方程

Equation with highest power 1. e.g. 2x + 3y = 7.

C
Coefficient係數

Number in front of unknown. In 2x, coefficient is 2.

C
Consistent有解

Has a solution. Two lines intersect = has solution.

3Step by step Steps

  1. 1. What are simultaneous equations?A pair of simultaneous linear equations consists of two linear equations sharing the same two unknowns, usually x and y, such as x + y = 5 and x − y = 1. One equation alone has infinitely many solutions; the goal is the single pair (x, y) satisfying both at once. 'Linear' means the unknowns appear only to the first power — no x² or xy terms.
  2. 2. Method 1: SubstitutionSubstitution works best when one equation is already in the form 'y = ...' or 'x = ...'. For y = x + 1 and x + y = 5: first replace y in the second equation with the whole expression (x + 1), giving x + (x + 1) = 5; then collect like terms to get 2x + 1 = 5, so 2x = 4 and x = 2. Two unknowns have temporarily become one, which can be solved directly.
  3. 3. Substitution: find the other unknownFinding x = 2 is not the end: substitute it back into the simplest original equation to obtain y. From y = x + 1 we get y = 2 + 1 = 3, so the solution is x = 2, y = 3. A common mistake is stopping after x — a pair of simultaneous equations always needs both values, stated clearly, and it is worth checking them in the other equation too.
  4. 4. Method 2: EliminationElimination is fastest when the two equations carry equal or opposite coefficients for one unknown. For x + y = 5 and x − y = 1, adding the equations gives (x + y) + (x − y) = 2x on the left and 5 + 1 = 6 on the right; the y terms cancel, leaving 2x = 6, so x = 3. If the coefficients differ, multiply one equation by a suitable number first to make them match, then add or subtract.
  5. 5. Elimination: find the other unknownSubstitute x = 3 back into the first equation x + y = 5: 3 + y = 5 gives y = 2, so the solution is x = 3, y = 2. Choose the simplest equation for this back-substitution to keep the arithmetic light. If decimals or fractions appear without reason, an earlier elimination step is probably wrong — retrace the steps instead of forcing the wrong numbers onwards.
  6. 6. Check and exam tipsCheck the pair in both original equations: x + y = 3 + 2 = 5 ✓ and x − y = 3 − 2 = 1 ✓; only when both hold is the solution confirmed, because satisfying one equation alone still leaves infinitely many pairs. For the exam: turn word problems into two equations first, and remember to answer the original question — a price or a quantity — rather than only the bare values of x and y.

4Diagrams Diagrams

聯立方程:代入消元法 Substitution methody = 2x + 1 …… ①x + y = 7 …… ②① 代入 ②:x + (2x + 1) = 73x + 1 = 7 → x = 2代返 ①:y = 2(2) + 1 = 5答:x = 2,y = 5檢查:2 + 5 = 7 ✓|兩條直線嘅交點就係共同解——圖像法都搵到同一點揀方法:一條已經寫明 y= → 代入快;兩條都齊 → 加減消元快
Fig. 1: Simultaneous equations

5Worked example Example

Solve: 2x + y = 7, x − y = 2

  1. Add both: (2x+y) + (x−y) = 7+2
  2. 3x = 9 → x = 3
  3. Substitute into x−y=2: 3−y=2 → y=1
  4. Answer: x=3, y=1
  5. Answer: x=3, y=1

6Common mistakes Mistakes

✗ Substituting wrong: y=x+1 into x+y=5 becomes x+x=5 ✗
✓ Substitute the whole x+1: x + (x+1) = 2x + 1 = 5 → x = 2.
✗ Elimination wrong: x+y=5, x−y=1, add = 2x+2y=6 ✗
✓ y must cancel, leaving 2x = 6 → x = 3.
✗ Stop after finding x, don't find y ✗
✓ Simultaneous equations have TWO answers! Find x AND y.
✗ Checking only one equation ✗
✓ Must substitute into BOTH equations to verify!

7Quick check Quick check

Q1Solve: x + y = 5, x − y = 1

Q2Solve: y = x + 1, x + y = 5

Q3Solve: 2x + y = 7, x − y = 2

Q4Solve: x + y = 10, x = 4

Q5Solve: 3x + y = 11, x + y = 5

8Recap Recap

  • Simultaneous equations = 2 equations, 2 unknowns
  • Substitution: plug one into the other
  • Elimination: add/subtract to cancel one unknown
  • After finding x, still need to find y
  • Check both equations to be safe

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