Probability Basics

Foundation

Probability P(event) = number of favourable outcomes ÷ total number of equally likely outcomes. It ranges from 0 (impossible) to 1 (certain). All mutually exclusive outcomes must add up to 1.

For:Secondary 3 Mathematics · Unit:Probability & statistics · Lesson 25 of 37 in the learning path

After this lesson, you can:
  • P = favourable ÷ all outcomes
  • Probability is 0 to 1
  • Not happening = 1 − happening
數學Mathematics

1Summary 重點摘要

Probability P(event) = number of favourable outcomes ÷ total number of equally likely outcomes. It ranges from 0 (impossible) to 1 (certain). All mutually exclusive outcomes must add up to 1.

2Vocabulary cards Vocabulary

P
Probability概率

Chance of an event happening, from 0 (impossible) to 1 (certain).

E
Event事件

The outcome we care about, e.g. 'rolling a 6'.

S
Sample space樣本空間

All possible outcomes. Dice sample space is {1,2,3,4,5,6}.

F
Favourable outcome有利結果

Number of outcomes that match the event. Want even number, favourable are 2,4,6 (3).

R
Random隨機

Every outcome equally likely, can't predict.

C
Complement補事件

The event not happening. P(not 6) = 1 − P(6).

E
Equally likely等可能

Every outcome has same chance. Fair die each face 16.

P
Probability line概率線

Line from 0 (impossible) to 1 (certain), showing probability size.

3Step by step Steps

  1. What probability is, and its rangeProbability measures how likely an event is, always between 0 and 1: 0 impossible, 1 certain, 0.5 an even chance, also writable as a percentage (0.5 = 50%). Everyday anchors: drawing a white ball from a bag holding only red ones has probability 0; a fair coin gives heads with probability 0.5; the sun rising in the east has probability 1. Any result above 1 or below 0 is certainly wrong — re-check at once whether numerator and denominator were swapped or the favourable outcomes miscounted.
  2. The basic formulaWhen every outcome is equally likely, P(event) = favourable outcomes ÷ all possible outcomes. Rolling a fair die, the favourable outcome is {6} — one of them; all outcomes are {1, 2, 3, 4, 5, 6} — six in all; hence P(6) = 1 ÷ 6. The formula presumes every outcome equally likely: the die must be fair. A loaded die gives some faces a better chance than others, the assumption breaks, and the formula no longer applies.
  3. Example: rolling an even numberFor a fair die, the favourable outcomes for an even number are {2, 4, 6} — three of them — against six outcomes in all, so P(even) = 3 ÷ 6 = 12 = 0.5 = 50%. The same probability may be written as the fraction 12, the decimal 0.5 or 50%, all equivalent; follow the form the question requests, or give all three. List favourable outcomes one by one to avoid mental slips: 'greater than 4' means {5, 6}, two outcomes, not one.
  4. Complement: subtract from 1Sometimes the probability of 'not happening' is far easier than that of 'happening'; then use the complement rule P(not A) = 1 − P(A). Since P(6) = 16, the probability of not rolling a six is 1 − 16 = 56. An event and its complement together cover every possibility, so their probabilities sum to exactly 1. Whenever a question says 'at least once' or 'not', ask first whether the complement gives a shorter path — for at-least-one-six problems it usually does.
  5. The playing-card exampleFrom a standard 52-card deck (no jokers), one card is drawn at random: 13 hearts give P(heart) = 13 ÷ 52 = 14, and four aces give P(A) = 4 ÷ 52 = 113. The key is knowing the deck's structure: 13 cards per suit and four cards of each rank must be memorised. If a condition is attached — say 'given the card is a heart, find the probability it is the ace of hearts' — the denominator shrinks to 13, a first taste of conditional probability met formally in senior forms.
  6. Independence and the gambler's fallacyFour essentials: probability lies between 0 and 1; all outcomes' probabilities sum to 1; fair means every outcome equally likely; and successive trials are independent. The commonest misconception is the gambler's fallacy — after five sixes in a row, believing the next roll cannot be a six. A die has no memory: the chance is still 16. Likewise a lottery number drawn twice in a row is no less likely next time. Understanding independence guards against many traps in everyday judgement.

4Diagrams Diagrams

概率尺:由 0 到 1 The probability scale0不可能 impossible0.5一半機會 even chance1必然 certain0.25 好似會落雨0.9 好大機會概率 P(E) = 有利結果數 ÷ 全部等可能結果數——永遠喺 0 同 1 之間驗機:擲骰仔出「7」= 0/6 = 0;出單數 = 3/6 = 0.5;出 1–6 = 1全部可能結果加埋 = 1——呢條係概率題嘅萬能檢查
Fig. 1: The probability scale

5Worked example Example

Example: from a 52-card deck without jokers, one card is drawn; find P(heart) and P(not a heart).

  1. Fix the sample space: 52 cards, each equally likely.
  2. Count favourable outcomes: 13 hearts, so P(heart) = 1352.
  3. Simplify: 1352 = 14.
  4. Complement rule: P(not a heart) = 1 − 14 = 34.
  5. Check: non-hearts number 52 − 13 = 39, and 3952 = 34, agreeing.
  6. Conclusion: the two probabilities sum to 14 + 34 = 1, as the complement property demands.
  7. Answer: P(heart) = 14 and P(not a heart) = 34 — divide the favourable count by 52 for the event, subtract from 1 for the complement, and confirm the two sum to exactly 1.

6Common mistakes Mistakes

✗ Rolled 6 five times, next time can't be 6 ✗
✓ Independent! Next roll still 16, doesn't matter what happened before.
✗ Probability > 1: P = 32 ✗
✓ Probability is always 0 to 1. 32 = 1.5 > 1, definitely wrong.
✗ Drawing hearts = 1313 = 1 ✗
✓ Denominator is all outcomes: 1352 = 14. Don't just count hearts.
✗ Rolling even = 33 = 1 ✗
✓ Even has 3, total 6: 36 = 12. Denominator is total, not favourable.

7Quick check Quick check

Q1Fair die, probability of rolling 3?

Q2Fair die, probability of odd number?

Q352-card deck, probability of drawing a King?

Q4Die, probability of NOT rolling 6?

Q5Bag has 3 red, 2 blue, probability of red?

8Recap Recap

  • P = favourable ÷ all outcomes
  • Probability is 0 to 1
  • Not happening = 1 − happening
  • Each trial independent, don't be affected by previous results
  • Fair = every outcome equally likely

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