Circumference (intro)

Foundation

Circumference = diameter × π (~3.14).

For:Primary 5 Mathematics · Unit:Measures · Lesson 20 of 36 in the learning path

After this lesson, you can:
  • Circumference: C = πd or C = 2πr
  • π ≈ 3.14, the ratio circumference ÷ diameter
  • Diameter = 2 × radius
數學Mathematics

1Summary 重點摘要

Circumference = diameter × π (~3.14).

2Vocabulary cards Vocabulary

C
Circle圓

A shape whose points are all equidistant from the centre.

C
Centre圓心

The middle point of the circle, usually called O.

R
Radius半徑(r)

The distance from centre to edge, e.g. 5 cm.

D
Diameter直徑(d)

A chord through the centre touching both sides; d = 2r.

C
Circumference圓周

The distance all the way around the circle.

P
Pi (π)圓周率(π)

Circumference ÷ diameter for ANY circle, about 3.14.

P
Perimeter周界

Total boundary length; for a circle it is the circumference.

S
Semicircle半圓

Half a circle; perimeter = πr + d (arc plus diameter).

3Step by step Steps

  1. Step 1: Parts of a circleThe middle point is the centre O; the radius r runs from the centre to the edge; the diameter d passes through the centre with both ends on the circle. A circle of radius 5 has diameter 10, because d = 2r. Knowing these parts keeps the formulas straight.
  2. Step 2: The two formulasWith the diameter use C = πd; with the radius use C = 2πr. They are really one formula, because putting d = 2r into πd gives 2πr. Pick whichever matches what you know.
  3. Step 3: What π isMeasure the circumference and the diameter of any round object, such as a tin or a wheel, and divide: the answer is always about 3.14. This fixed ratio is π, the same for every circle.
  4. Step 4: Using the diameterFor d = 10 cm: C = 3.14 × 10 = 31.4 cm, shifting the decimal point one place right. The circumference should be a little more than three diameters, and 31.4 fits that expectation.
  5. Step 5: Using the radiusFor r = 3 cm: C = 2 × 3.14 × 3. First 2 × 3.14 = 6.28, then 6.28 × 3 = 18.84 cm. Working out 2π first can be reused whenever the radius changes.
  6. Step 6: Semicircle perimeterFor a semicircle of d = 10: the arc is half the circle, 3.14 × 10 ÷ 2 = 15.7, and the straight diameter must be added: 15.7 + 10 = 25.7 cm. Counting only the arc and forgetting the straight edge is the classic mistake.

4Diagrams Diagrams

圓周:轉一圈有幾長 Circumference直徑 d碌一圈:圓周 ≈ 直徑嘅 3 倍幾圓周 = π × 直徑(C = πd)π ≈ 3.14直徑 7 cm 嘅餅:圓周 ≈ 3.14 × 7 ≈ 22 cm
Fig. 1: Circumference

5Worked example Example

Example: a circular garden has diameter 10 m. How long is one lap around it? (Use π = 3.14)

  1. The diameter is given, d = 10 m, so choose the formula C = πd.
  2. Substitute: C = 3.14 × 10.
  3. Calculate: 3.14 × 10 = 31.4, shifting the point one place right.
  4. Attach the unit: the circumference is 31.4 m.
  5. Sense check: one lap should be a bit over three diameters, and 31.4 ÷ 10 = 3.14 matches π.
  6. Answer: One lap around the garden is about 31.4 m. With diameter 10 m the formula C = πd gives 3.14 × 10 = 31.4. As a check, the ratio of circumference to diameter is 31.4 ÷ 10 = 3.14, which is exactly π, so the calculation agrees with the meaning of circumference.

6Common mistakes Mistakes

✗ Using π = 3: C = 3 × 10 = 30.
✓ At primary level π ≈ 3.14: 3.14 × 10 = 31.4.
✗ Mixing radius with diameter: taking r = 5 as d.
✓ Sort it out first: d = 2r, so r = 5 means d = 10.
✗ Swapping circumference with area: using πr² for the perimeter.
✓ Circumference is 2πr or πd; πr² is area (next lesson).
✗ Counting only the arc for a semicircle.
✓ Semicircle perimeter = arc + diameter: 15.7 + 10 = 25.7.

7Quick check Quick check

Q1Diameter 10 cm. Circumference? (π = 3.14)

Q2Radius 4 cm. Circumference?

Q3What is π approximately?

Q4What is the relation between radius and diameter?

Q5Perimeter of a semicircle with diameter 10 cm?

8Recap Recap

  • Circumference: C = πd or C = 2πr
  • π ≈ 3.14, the ratio circumference ÷ diameter
  • Diameter = 2 × radius
  • A semicircle's perimeter includes the diameter
  • Circumference is a length in cm/m, not cm²

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