Uniform Circular Motion and Gravitation
AdvancedAn object moving in a circle needs a centripetal force towards the centre, with acceleration v²/r; gravitation acts on everything with an inverse-square law, and when gravity supplies the centripetal force, planets and satellites orbit stably.
- In uniform circular motion the speed is constant but the velocity direction keeps changing, giving a centripetal acceleration towards the centre
- a = v²/r and F = mv²/r; the centripetal force is supplied by real forces — tension, friction or gravity — not a new force
- Universal gravitation: F = Gm₁m₂/r² with G = 6.67 × 10⁻¹¹ N m² kg⁻², where r is the centre-to-centre distance
文體小知識:科學知識說明文——講解勻速圓周運動的向心加速度與向心力,再由萬有引力推出衛星軌道規律,是力學的壓軸一課。
§Text Passage
1A roller-coaster car sweeps over the top of a vertical loop without falling, and the Moon has circled the Earth for billions of years without flying away — both are the same physics: circular motion and gravitation. An object moving along a circle at constant speed is in uniform circular motion. Although the speed is constant, the direction of velocity changes from moment to moment, and since velocity is a vector, the object is in fact accelerating all the time, requiring a force towards the centre to keep bending its path.
2There are two languages for describing circular motion. One is linear speed, how fast the object travels along the circle; the other is angular velocity, how fast it sweeps through angle, with one revolution corresponding to an angle of 2π radians. The radius links them: linear speed equals radius times angular velocity. The time for one revolution is the period — the shorter the period, the faster the spin. On a carousel the horses on the outer ring and inner ring share the same period, yet the outer ones travel a longer distance each lap and so move faster: exactly what this relation says.
3The acceleration pointing towards the centre is called centripetal acceleration, equal to speed squared divided by radius. By Newton's Second Law, the object must experience a net force towards the centre, the centripetal force, equal to mass times speed squared divided by radius. Remember: centripetal force is not a new kind of force — real forces such as string tension, friction or gravity take on the role. Once the string snaps, the stone flies off along the tangent, not radially outwards.
4Newton went further: every pair of objects in the universe attracts each other with a force proportional to the product of their masses and inversely proportional to the square of their separation — Newton's law of universal gravitation. The constant G is about 6.67 × 10⁻¹¹ N m² kg⁻², an extremely small number, so the attraction between everyday objects is imperceptible; yet on the scale of planets and stars, gravity rules everything. Gravitational field strength is the force per unit mass at a point: about 9.8 N kg⁻¹ at the Earth's surface, decreasing with height.
5An artificial satellite can circle the Earth indefinitely precisely because gravity supplies exactly the centripetal force needed: gravity keeps pulling the satellite towards the Earth, while its tangential speed is large enough that it keeps 'falling' yet never reaches the ground, settling into a stable orbit. The higher the orbit, the weaker the gravity, the smaller the required speed and the longer the period. This lesson mobilises every mechanics tool since S4 — a grand finale for mechanics. Next lesson we leave the sky and return home to circuits and domestic electricity.
1Summary 重點摘要
An object moving in a circle needs a centripetal force towards the centre, with acceleration v²/r; gravitation acts on everything with an inverse-square law, and when gravity supplies the centripetal force, planets and satellites orbit stably.
2Vocabulary cards Vocabulary
Motion along a circular path at constant speed; the speed is constant but the direction of velocity keeps changing.
The angle swept per unit time, in rad s⁻¹; equal to 2π divided by the period.
The time for one complete revolution; the reciprocal of the period is the frequency of rotation.
The acceleration of circular motion directed towards the centre, of magnitude v²/r.
The net force towards the centre that keeps an object in circular motion, mv²/r, provided by real forces such as tension, friction or gravity.
Any two objects attract each other with a force proportional to the product of their masses and inversely proportional to the square of their separation: F = Gm₁m₂/r².
The constant G in the law of gravitation, 6.67 × 10⁻¹¹ N m² kg⁻².
The gravitational force per unit mass at a point, GM/r²; about 9.8 N kg⁻¹ at the Earth's surface.
An object orbiting a planet or star; for an artificial satellite, gravity supplies the centripetal force for the orbit.
The path of an object moving around a celestial body under gravity; the speed of a circular orbit is v = √(GM/r).
3Step by step Steps
- Step 1: Uniform circular motion and the direction mythAn object moving along a circular path at constant speed is in uniform circular motion. Constant speed does not mean zero acceleration: velocity is a vector with magnitude and direction, and in circular motion the direction changes every instant, so there must be an acceleration directed towards the centre. For example, a cabin on a Ferris wheel moves at a steady rate and riders feel calm, yet the cabin's velocity direction is turning all the time — the change is just smooth and easily missed. If an exam question asks whether uniform circular motion has acceleration, the answer is yes: a classic conceptual trap often paired with Newton's First Law.
- Step 2: Angular velocity, period and linear speedRotation speed is described by angular velocity: the angle swept per second, in rad s⁻¹. One revolution is 2π radians, so angular velocity equals 2π divided by the period; linear speed equals the circumference 2πr divided by the period, and also equals radius times angular velocity. For example, two points on a rotating dish — one near the centre, one near the rim — share the same period and angular velocity, but the rim point has a larger radius and therefore a larger linear speed. In calculations, first identify whether the question gives linear speed or angular velocity, then pick the matching formula; reading the question carefully is half the battle.
- Step 3: Centripetal acceleration a = v²/rThe acceleration of circular motion points towards the centre and is called centripetal acceleration, of magnitude speed squared over radius: a = v²/r. The larger the speed or the smaller the radius, the more abruptly the direction changes and the larger the acceleration. For example, a car rounding a sharp bend (small radius) throws passengers outwards far more noticeably than a gentle bend at the same speed, precisely because the smaller radius gives a larger centripetal acceleration. Watch the units: speed in m s⁻¹ and radius in m give acceleration in m s⁻². The formula contains no mass — it is purely kinematic, and it pairs with the dynamical formula in the next step.
- Step 4: Where the centripetal force comes fromBy Newton's Second Law, acceleration demands a net force: the net force supplying centripetal acceleration is the centripetal force, F = mv²/r, always pointing to the centre. It is not an extra new kind of force — real forces take on the role: string tension for a ball whirled horizontally, friction for a car turning, gravity plus track pressure for a coaster at the loop's top. For example, whirl a stone on a string in a horizontal circle: the instant the string snaps, the tension vanishes and the stone flies straight off along the tangent, obeying Newton's First Law — it never drifts radially outwards. Never draw centripetal force as an additional arrow on top of the real forces in a free-body diagram.
- Step 5: Newton's law of universal gravitationNewton showed that any two objects in the universe attract each other: the force is proportional to the product of the masses and inversely proportional to the square of the distance between their centres, F = Gm₁m₂/r², with G ≈ 6.67 × 10⁻¹¹ N m² kg⁻². For example, double the separation and the force falls to a quarter; double both masses and the force quadruples. Note that r is the distance between the centres of the two bodies — for a satellite it is the Earth's radius plus the orbital altitude, not the altitude alone. This is the most common slip in calculations. Gravity is feeble in daily life, yet it governs planets, tides and galaxies.
- Step 6: Gravitational field strength and gGravitational field strength is defined as the gravitational force per unit mass at a point, equal to GM/r², in N kg⁻¹. At the Earth's surface it is about 9.8 N kg⁻¹ — the same number as the free-fall acceleration 9.8 m s⁻². For example, the Moon's much smaller mass gives a surface field of only about 1.6 N kg⁻¹: a 60 kg astronaut weighed about 588 N on Earth but only about 96 N on the Moon, which is why Apollo astronauts could hop so easily; weight changes with location, mass does not. The field weakens with height, so gravity on orbital altitudes is markedly smaller than at the surface.
- Step 7: Satellite orbits — gravity as the centripetal forceFor a satellite in circular orbit, universal gravitation supplies exactly the centripetal force: GMm/r² = mv²/r; cancelling m gives the orbital speed v = √(GM/r), independent of the satellite's own mass. For example, a satellite skimming the Earth moves at about 7.9 km s⁻¹ and completes a lap in roughly an hour and a half; a geostationary satellite orbits far higher and slower with a period of exactly 24 hours, matching the Earth's rotation so it hangs over the same spot — the basis of communications satellites. In exams, write 'gravity provides the centripetal force', then set up the equation: this framework earns marks almost every year in long questions.
4Diagrams Diagrams
5Worked example Example
Example: (a) A roller-coaster car passes the top of a vertical loop of radius 5 m. Find the minimum speed at the top for the car to stay on the track. Take g = 9.8 m s⁻². (b) Hence explain why an artificial satellite in circular orbit does not fall to the ground.
- At the top, gravity mg acts downward and the normal force N from the track also acts downward (the track is above the car); the resultant supplies the centripetal force: mg + N = mv²/r
- Minimum speed occurs at the verge of losing contact, where N = 0
- Hence mg = mv²/r; cancelling m gives v² = gr
- Substitute the numbers: v = √(9.8 × 5) = √49 = 7 m s⁻¹
- Part (b): gravity on the satellite supplies exactly the centripetal force, pulling it towards the Earth; with sufficient tangential speed, the satellite keeps 'falling' towards the centre while the curved ground falls away beneath it, so it never lands and maintains a stable orbit
- Answer: (a) Minimum speed at the top: v = √(gr) = √(9.8 × 5) = 7 m s⁻¹; any slower and gravity would exceed the required centripetal force, so the car would leave the track. (b) The satellite stays aloft because gravity acts as the centripetal force, accelerating it towards the centre, while its tangential speed keeps it circling — the balance gives a stable orbit. Key moves: state the force condition, write the formula, substitute with units.
6Common mistakes Mistakes
7Quick check Quick check
Q1Does uniform circular motion involve acceleration? Why?
Q2If the radius of circular motion doubles while the speed stays the same, how does the centripetal force change?
Q3A 0.5 kg stone on a string whirls in a horizontal circle of radius 0.8 m at 2 m s⁻¹. Find the tension in the string.
Q4If the separation of two objects halves, how many times does the gravitational force become?
Q5Why does an artificial satellite not fall to the ground?
8Recap Recap
- In uniform circular motion the speed is constant but the velocity direction keeps changing, giving a centripetal acceleration towards the centre
- a = v²/r and F = mv²/r; the centripetal force is supplied by real forces — tension, friction or gravity — not a new force
- Universal gravitation: F = Gm₁m₂/r² with G = 6.67 × 10⁻¹¹ N m² kg⁻², where r is the centre-to-centre distance
- Gravitational field strength g = GM/r² is about 9.8 N kg⁻¹ at the Earth's surface and decreases with height; mass stays constant while weight varies
- In a circular satellite orbit, gravity is the centripetal force and v = √(GM/r); the higher the orbit, the smaller the speed and the longer the period