Atomic Models and Nuclear Energy
FoundationAtomic models evolved from Thomson's plum pudding through Rutherford's nuclear model to Bohr's energy levels; mass number and atomic number balance across nuclear equations; fission and fusion convert mass defect into vast energy via E = mc², and nuclear power has both merits and risks.
- An atom has a nucleus of protons and neutrons with electrons outside; nuclide notation gives A and Z, and neutrons = A − Z
- The model evolved from Thomson's plum pudding, through Rutherford's scattering proof of the nuclear model, to Bohr's discrete energy levels
- Isotopes share protons but differ in neutrons; nuclear equations balance in both mass number and atomic number
文體小知識:科學知識說明文——沿原子模型的演進講起,介紹同位素、裂變聚變與質能關係,最後評議核能的利與弊。
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1At the centre of an atom sits a tiny, dense nucleus of positively charged protons and uncharged neutrons, with negatively charged electrons orbiting outside. A particular nucleus is described by its nuclide notation: the mass number A — the total of protons and neutrons — written top-left, and the atomic number Z — the proton number — bottom-left. Carbon-12, for instance, is written with A = 12 and Z = 6, and subtracting gives 6 neutrons. The atomic number fixes an element's identity; the mass number distinguishes the different nuclides of one element.
2The atomic model went through several revolutions. Thomson discovered the electron in cathode-ray experiments and proposed the plum pudding model: positive charge spread evenly through the atom with electrons embedded like fruit in a pudding. From 1909, the alpha-scattering experiments directed by Rutherford redrew the picture: the overwhelming majority of α particles passed straight through gold foil, a few deflected sharply, and some even bounced back — the positive charge and mass must be concentrated in a tiny nucleus. This is the nuclear model, in which most of the atom is empty space.
3In 1913 Bohr went a step further: electrons can occupy only specific energy levels, so atomic energy is not continuous; an electron absorbing energy jumps upward, and falling back it emits light of specific energies. The hydrogen spectrum's set of discrete bright lines is firm evidence for these levels. The story of the atom shows scientific models being revised by new evidence, with experiment always the referee — that empirical spirit is physics' most precious tradition.
4Heavy nuclei can split: a neutron strikes uranium-235, the nucleus breaks into two lighter nuclei, releasing two or three neutrons and a great deal of energy; the fresh neutrons strike other uranium nuclei and a chain reaction follows. Nuclear power plants absorb surplus neutrons with control rods so the reaction proceeds steadily and under control. Light nuclei can instead fuse into heavier ones — the Sun has shone for eons on the fusion of hydrogen nuclei — yet controlled fusion power remains at the experimental stage, not yet commercial.
5In both fission and fusion, the total mass after the reaction is slightly less than before, and that mass defect converts into enormous energy through Einstein's mass-energy relation E = mc². Nuclear power uses little fuel and emits no greenhouse gases, but radioactive waste must be isolated for extremely long times, and accident risk cannot be ignored. Weighing the pros and cons against fossil fuels is a favourite discussion question in long papers — prepare both sides.
1Summary 重點摘要
Atomic models evolved from Thomson's plum pudding through Rutherford's nuclear model to Bohr's energy levels; mass number and atomic number balance across nuclear equations; fission and fusion convert mass defect into vast energy via E = mc², and nuclear power has both merits and risks.
2Vocabulary cards Vocabulary
The number of protons Z in a nucleus, fixing the element's identity and chemical properties.
The total number A of protons and neutrons in a nucleus.
The notation for a nuclide: mass number A top-left, atomic number Z bottom-left, element symbol to the right.
Nuclides with the same atomic number but different neutron numbers; chemically identical, though their nuclear properties may differ greatly.
Thomson's atomic model: positive charge spread evenly with electrons embedded like plums in a pudding.
The α-particle-on-gold-foil experiment: a few sharp deflections and rebounds proved a tiny, positively charged nucleus.
The discrete states electrons may occupy in Bohr's model; transitions absorb or emit specific energies.
The splitting of a heavy nucleus (e.g. uranium-235) by neutron impact into lighter nuclei with released neutrons and energy; the energy source of nuclear power plants.
The merging of light nuclei into heavier ones at extreme temperature and pressure; the Sun's energy source.
Einstein's equation E = mc²: the energy from a mass defect equals the lost mass times the speed of light squared.
3Step by step Steps
- Step 1: Atomic structure and nuclide notationAn atom consists of a central nucleus with electrons outside: the nucleus holds positively charged protons and uncharged neutrons, together called nucleons; tiny in volume, it carries almost all the mass. Nuclide notation writes the mass number A top-left and the atomic number Z bottom-left. For example, uranium-238 is written with A = 238, Z = 92, so neutrons = 238 − 92 = 146. The nuclear charge equals the proton number, and a neutral atom has as many electrons as protons; these basics underpin every nuclear equation and calculation, so drill them until automatic.
- Step 2: Thomson and the plum pudding modelIn 1897 Thomson discovered the electron in cathode-ray experiments: the rays deflected in electric and magnetic fields, proving they were negatively charged particles far lighter than atoms. Since the atom is neutral, positive charge had to live inside it, and Thomson proposed the plum pudding model: positive charge spread evenly through the atom with electrons embedded like plums in a pudding. For example, imagine a sphere of positively charged 'batter' with electrons suspended and vibrating within. The model explained neutrality and ionization, but it would not survive the alpha-scattering test of the next step.
- Step 3: Rutherford scattering and the nuclear modelRutherford had α particles fired at an extremely thin gold foil: the vast majority sailed straight through, showing the atom is mostly empty; a few deflected through large angles, and some rebounded almost straight back, as if striking something massive and positively charged. The plum pudding model cannot explain large-angle rebounds — evenly spread charge could never repel an α particle hard enough. Rutherford therefore proposed the nuclear model: all positive charge and nearly all mass concentrate in a tiny central nucleus. For example, if an atom were enlarged to a stadium, its nucleus would be a single bean at the centre.
- Step 4: Bohr's model and energy levelsBy classical physics an orbiting electron should radiate energy continuously and spiral into the nucleus — stable atoms could not exist. In 1913 Bohr proposed that electrons can occupy only specific energy levels, so atomic energy is quantised; absorbing exactly the gap between two levels jumps the electron upward, and dropping back it emits light of the matching energy. For example, the hydrogen spectrum consists of discrete bright lines at fixed wavelengths, each matching a transition between a pair of levels; if energy were continuous the spectrum would be a rainbow band. Energy levels underpin atomic emission and lasers alike.
- Step 5: Isotopes and balancing nuclear equationsIsotopes share an atomic number but differ in neutron count; their chemical properties are essentially identical while their nuclear properties can differ completely — some stable, some radioactive. Nuclear equations must balance: the mass numbers on both sides add up equally, and so do the atomic numbers. For example, the α decay of uranium-238: the nucleus with A = 238, Z = 92 emits an α particle (A = 4, Z = 2) and becomes thorium with A = 234, Z = 90 — 238 = 234 + 4 and 92 = 90 + 2, both rows balanced. Unbalanced equations are the most common loss in radioactivity questions; check every term after writing.
- Step 6: Fission and the chain reactionWhen a neutron strikes uranium-235, the nucleus splits into two medium-mass nuclei (for example barium-141 and krypton-92), releasing 2 to 3 fast neutrons and a great deal of energy; the fresh neutrons strike other uranium nuclei, and the reaction spreads tenfold and hundredfold — a chain reaction. Nuclear plants absorb surplus neutrons with control rods to hold the rate steady, and use moderators to slow fast neutrons so they trigger fission more readily. For example, the complete fission of 1 kg of uranium-235 releases energy comparable to burning about 2700 tonnes of coal — an extraordinary energy density. Fission products are mostly radioactive, which is what makes waste so troublesome.
- Step 7: Fusion, E = mc² and the nuclear debateLight nuclei — such as the hydrogen isotopes deuterium and tritium — fuse into heavier nuclei at extreme temperature and pressure, releasing energy by the same mass-energy relation; the Sun's core converts about 4 million tonnes of matter to energy every second through fusion. E = mc² shows that a minuscule mass defect carries enormous energy: for example, 1 gram of mass defect releases about 9 × 10¹³ J, the heat of thousands of tonnes of coal. Nuclear power's strengths: little fuel, vast energy, no carbon dioxide in generation; its weaknesses: waste isolated for millennia, high construction and decommissioning costs, accident and proliferation concerns. Discussion questions want both sides, with a measured conclusion.
4Diagrams Diagrams
5Worked example Example
Example: a nuclear reaction has a mass defect of 1 g (0.001 kg). Taking c = 3 × 10⁸ m s⁻¹, find the energy released in joules, and compare it roughly with burning coal (heat value about 3 × 10⁷ J kg⁻¹).
- Write the mass-energy relation: E = mc²
- Substitute: E = 0.001 × (3 × 10⁸)²
- Square the speed of light first: (3 × 10⁸)² = 9 × 10¹⁶ m² s⁻²
- Hence E = 0.001 × 9 × 10¹⁶ = 9 × 10¹³ J
- Compare: 9 × 10¹³ ÷ 3 × 10⁷ = 3 × 10⁶ kg — the heat of 3000 tonnes of coal, an immense energy density
- Answer: E = mc² = 0.001 × 9 × 10¹⁶ = 9 × 10¹³ J — roughly the heat of burning 3000 tonnes of coal. A tiny mass defect carries enormous energy, the source of both nuclear power and the Sun's light. Square first, then multiply; write powers of ten step by step to avoid order-of-magnitude slips.
6Common mistakes Mistakes
7Quick check Quick check
Q1What key conclusion followed from Rutherford's α-scattering experiment?
Q2What are isotopes? Give one example.
Q3Balance: uranium-238 (A = 238, Z = 92) undergoes α decay. What nuclide is produced?
Q4A nuclear reaction has a mass defect of 2 g. How much energy is released? (c = 3 × 10⁸ m s⁻¹)
Q5How do fission and fusion differ? Give one example of each.
8Recap Recap
- An atom has a nucleus of protons and neutrons with electrons outside; nuclide notation gives A and Z, and neutrons = A − Z
- The model evolved from Thomson's plum pudding, through Rutherford's scattering proof of the nuclear model, to Bohr's discrete energy levels
- Isotopes share protons but differ in neutrons; nuclear equations balance in both mass number and atomic number
- Fission (uranium-235 chain reaction; power plants) and fusion (the Sun) both release vast energy from mass defect via E = mc²
- Nuclear energy is fuel-thrifty and carbon-free in operation, but waste isolation and accident risk fuel the debate — present both sides in discussion answers